3 years ago

4p+25=6(p-3)-3(4-3p)

1 answer:

3 0

P = 5 .............................................
this is how=

first you expand the second equation
25 + 4p = -18 + -12 + 6p + 9p

then you add the like terms in the second equation:
25 + 4p = -30 + 15p
then this is how=
25+30 = 15p -4p
55=11p

p= 5

You might be interested in

A shipping company charges based on calculations of the volume of a rectangular box and the sum of the dimensions of the box. A

Allushta [10]

Answer:

A shipping company charges based on calculations of the volume of a rectangular box and the sum of the dimensions of the box. A square rectangular...

Step-by-step explanation:

7 0

3 years ago

Equal set is equivalent set but equivalent set not need equal set? why

nasty-shy [4]

Equal sets have the exact same elements, so they must have the same number of elements. Therefore, equal sets must also be equivalent. No, not all equivalent sets are also equal sets

6 0

3 years ago

Find the area of the following triangle: 18 9 11 14 Note: Figure not to scale.

Nataly [62]

Answer:

sorry but where is the triangle ️

3 0

2 years ago

TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?

egoroff_w [7]

Answer:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

Step-by-step explanation:

$3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12$

Taking square root both sides, we get

$\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}$