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AysviL [449]
3 years ago
5

#4- Brainliest and 5 stars to the correct answer- MUST SHOW WORK FOR THE POINTS

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0
Hello!!

\left \{ {{x = 3 cos t} \atop {y = 3 sin t}} \right. \\\left \{ {{y^2 = (3 cos t)^2} \atop {x^2= (3 sin t)^2}} \right. \\\left \{ {{y^2 = 3^2 cos^2 t} \atop {x^2= 3^2 sin^2 t}} \right.

Now add them,

x^2 + y^2 = 3^2cos^2t + 3^2sin^2t \\x^2 + y^2 = 3^2 * (cos^2t + sin^2t) ---> (REMEMBER: cos^2t + sin^2t = 1) \\x^2 + y^2 = 3^2 * 1 \\x^2 + y^2 = 3^2

Therefore, the center is at the origin (0,0), and the radius is 3. We eliminated the parameter!

Good luck :)
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Hope this helps.

Good luck ✅.

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4 years ago
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\text{Let Manas receives a commission of Rs. 5000 on sales of Rs. 65000}\\
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