An amphitheater charges $74 for each seat in Section A, $59 for each seat in Section B, and $28 for each lawn seat. There are th
ree times as many seats in Section B as in Section A. The revenue from selling all 13,000 seats is $503,000. Let x be the number of seats in A, y be the number of seats in B, and z be the number of lawn seats. Which system of equations represents the situation?
You need to do 2y+y+10+50=180. Then you'd combine like terms to make 3y+60=180 then to get rid of the sixty subtract it from 180 to make 3y=120 then divide by three to get y by itself so 120 divided by three is 40 which makes y whisk forty. Hope this helped.