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Nastasia [14]
2 years ago
11

An amphitheater charges $74 for each seat in Section A, $59 for each seat in Section B, and $28 for each lawn seat. There are th

ree times as many seats in Section B as in Section A. The revenue from selling all 13,000 seats is $503,000. Let x be the number of seats in A, y be the number of seats in B, and z be the number of lawn seats. Which system of equations represents the situation?
Mathematics
1 answer:
Ivenika [448]2 years ago
7 0

Answer:

<h2>(4x+z)=13000------1</h2><h2>(4x+z)13000=503000----2</h2>

Step-by-step explanation:

let x be the number of seats in A,

y be the number of seats in B, and

z be the number of lawn seats.

y=3x

the total number of seats is given by

(x+y+z)=13000

put y=3x

(x+3x+z)=13000

(4x+z)=13000------1

also

(4x+z)13000=503000----2

hence the systems of equation is

(4x+z)=13000------1

(4x+z)13000=503000----2

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Can you help me with my homework please
umka21 [38]

#4(a)

row-seat: 3- 13, 4-15, 5-17, 6-19, 7-21

(b)

the equation works for row 1 but not for any of the rows after this

Ex: Row 2, S=7(2)+2, this would equal 14 but there isn't 14 seats in row #2

(c)

S=2(1)+7, there is 9 seats in row 1

2(2)+7=11,  there is 11 seats in row 2

2(3)+7= 13, there is 13 seats in row 3

(d)

2(15)+7=37

2*15=30, 30+7=37

(e)

91=2(r)+7

91-7=2(r)+7-7

84=2(r)

84/2=2(r)/2

42=r, the row with 91 seats is row 42


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