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3 years ago

Simplify (p squared) to the power of 5

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

5 0

Answer:

p^10.

Step-by-step explanation:

(p^2)^5

= p^(2*5)

= p^10.

Free_Kalibri [48]3 years ago

3 0

Answer:

Step-by-step explanation:

(P²)^5 = P^(2×5) = P^10

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Please help fast i need help

Nutka1998 [239]

Answer:

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3. (-5)³ (-5×-5×-5) = -125

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2 years ago

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Lerok [7]

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2 years ago

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iVinArrow [24]

The next term in the sequence is double the previous term . so it would be the 3rd option (48,96,192)

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3 years ago

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Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

3 years ago

Doubling the sum of 5 and a number is equal to the same number decreased by 2. what is the equation

SVEN [57.7K]

Answer:

2(x + 5) = x - 2

⟹ x = -12

Step-by-step explanation:

Doubling the sum of 5 and a number is equal to the same number decreased by 2. What is the equation?

This word problem can be written as:

⟹ 2(x + 5) = x - 2

1. Distribute:

2(x) + 2(5) = x - 2

⟹ 2x + 10 = x - 2

2. Subtract x from both sides:

2x - x + 10 = x - x - 2

⟹ x + 10 = -2

3. Subtract 10 from both sides:

x + 10 - 10 = -2 - 10

⟹ x = -12

4. Check your work:

2(x + 5) = x - 2

2(-12 + 5) = -12 - 2

2(-7) = -20

⟹ -14 = -14 ✔

Learn more here:

brainly.com/question/17821973

3 0

1 year ago