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padilas [110]
3 years ago
9

a line passes through the point (-10,9) and has a slope of -1/2 write a equation in slope-intercept form for this line

Mathematics
1 answer:
Olegator [25]3 years ago
4 0

Answer:

\displaystyle y = -\frac{1}{2}x + 4

Step-by-step explanation:

9 = −½[−10] + b

5

\displaystyle 4 = b \\ \\ y = -\frac{1}{2}x + 4

I am joyous to assist you anytime.

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Answer:

boys : girls

4 : 5

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<u>total = 36</u>

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4 0
3 years ago
The function h(t) = 150 – 9t represents the height of a ball dropped from 150 feet after t seconds. What will the height of the
Alekssandra [29.7K]
After 1.4 seconds, t = 1.4.
h(t) = 150 - 9(1.4)
Multiply 9 by 1.4 to get 12.6. 
h(t) = 150 - 12.6 
Subtract 12.6 from 150 to get 137.4. 
h(t) = 137.4.
The height of the ball would be 137.4 after 1.4 seconds. 
Hope this helps!
3 0
3 years ago
Use the five number summary calculated in part C to create a box plot representing the data. Draw a box plot representing the fo
Alex777 [14]

Answer: Minimum: 20

Quartile Q1: 23.5

Median: 27

Quartile Q3: 31

Maximum: 35

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7 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
2 years ago
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