Question

Which standard form equation below correctly represents the quadratic function

Answer 1

Answer: 4) y = -1/3x² + 2x - 1

Step-by-step explanation:

Given :

y = $\frac{-1}{3}$$(x-3)^{2}$ + 2

Expanding (x-3)² will give :

$x^{2}$ - 6x + 9

substituting into the function , we have :

y =   $\frac{-1}{3}$$( [tex]x^{2}$ - 6x + 9 ) + 2

Expanding , we have

y = $\frac{-1}{3}$$x^{2}$ + 2x - 3 + 2

y = $\frac{-1}{3}$$x^{2}$ + 2x - 1