Answer:
- angles: 31.42°, 31.42°, 117.16°
- legs: 23.79 m
Step-by-step explanation:
The base angles can be found from the definition of the tangent function:
tan(base angle) = height/(half-base length)
base angle = arctan(12.4/20.3) ≈ 31.418°
Then the apex angle is double the complement of this:
apex angle = 2(90° -31.418°) ≈ 117.164°
The base angles are 31.42°, and the apex angle is 117.16°.
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The leg lengths can be computed from the Pythagorean theorem applied to the altitude and the half-base length.
leg length = √(12.4² +20.3²) = √565.85 ≈ 23.789 . . . . meters
The length of the legs is about 23.79 m.
Answer:
To get the solution, we are looking for, we need to point out what we know.
1. We assume, that the number 13 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 13 is 100%, so we can write it down as 13=100%.
4. We know, that x is 100% of the output value, so we can write it down as x=100%.
5. Now we have two simple equations:
1) 13=100%
2) x=100%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
13/x=100%/100%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 100% of 13
13/x=100/100
(13/x)*x=(100/100)*x - we multiply both sides of the equation by x
13=1*x - we divide both sides of the equation by (1) to get x
13/1=x
13=x
x=13
now we have:
100% of 13=13
Step-by-step explanation:
Have A Wonderful Day !!
Answer:
2x + y = 2.
Step-by-step explanation:
First find the slope of the required line by writing the line 2x + y = -5 in slope intercept form:
2x + y = -5
y = -2x - 5
- so the slope is -2.
Therefore the required equation is
y = -2x + 2 (where 2 is the y-intercept).
Converting to standard form:
y = -2x + 2
2x + y = 2.
Answer:
480 mm³
Step-by-step explanation:
The volume (V) of a pyramid is
V = 
area of base × height, hence
V = × 96 × 15 = 32 × 15 = 480
I think it would be 2 and 3 not too sure though
