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4 years ago

If A pizza restaurant offers 9 choices of vegetarian toppings for pizza In how many ways can you choose 4 toppings

1 answer:

4 0

You have to pay attention in this:
- The order doesn't matter
- No repetition
- You can not chose all available elements (just 4)
So in this case your formula must be: 9C4= 9!/(4!*(9-4)!) = 126 ways

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Which statement is not always true for a parallelogram?

VARVARA [1.3K]

<h3>Answer: B. Diagonals are congruent.</h3>

Explanation:

If the diagonals are congruent, then we'd have a rectangle. Any rectangle is a parallelogram, but not the other way around.

If we had a non-rectangular parallelogram, with none of the angles 90 degrees, then the diagonals will not be the same length.

Choices A, C and D are true for any parallelogram (rectangle or not).

3 0

3 years ago

Si una matriz tiene una fila o columna de ceros su determinante es:

Anni [7]

Answer:

es la A

Step-by-step explanation:

la columna es de cero ,es lo mismo

4 0

3 years ago

X, 2X + 11 and 4X - 3 are consecutive terms of an arithmetic sequence. Find the constant difference between terms. Give a formul

Anna007 [38]

Common difference between the terms is 36

Formula for nth term is $a_n=36n-11$

27th term is 961

Given :

X, 2X + 11 and 4X - 3 are consecutive terms of an arithmetic sequence

To Find:

We need to find the constant difference between the given terms and also find the nth term . Also find the 27th term .

To find the difference , we need to take the difference of consecutive terms

$2x+11-x=x+11\\\\4x-3=(2x+11)= 4x-3-2x-11=2x-14$

Both the common differences are equal

$x+11=2x-14\\Solve \; for \; x\\Subtract \; x\\11=x-14\\Add \; 14\\x=25$

First term is 25

second term is 2(25)+11=61

Difference is 61-25=26

Common difference = 36

Use nth term formula is

$a_n=a+(n-1)d\\a=25 (first term )\\d=36\\a_n=25+(n-1)(36)\\a_n=25+36n-36\\a_n=36n-11$

To find 27th term , replace n with 27

$a_{27}=36(27)-11=961$

Learn more : brainly.in/question/41142594

3 0

3 years ago

Georgia, a florist, charges $7.95 per flower bundle plus a $12 delivery charge per order. If Charlie orders 8 flower bundles and

Daniel [21]

Answer:

75.6

Step-by-step explanation

HOPE I HELPED ;)

7 0

3 years ago

Read 2 more answers

Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>

Ksju [112]

Step-by-step explanation:

$(\sec A - \csc A)(1 + \cot A + \tan A)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)$

$=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)$

$=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)$

$=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}$

$=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}$

$=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}$

$=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}$

$=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)$

$=\sec^2A\csc A - \csc^2A\sec A$

5 0

3 years ago