Whats the term for climate near equator
2 answers:
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Answer:
Distance, d = 61.13 ft
Explanation:
It is given that,
Initial speed of the car, u = 50 mi/h = 73.34 ft/s
Finally, it stops i.e. v = 0
Deceleration of the car,
We need to find the distance covered before the car comes to a stop. Let the distance is s. It can be calculated using third law of motion as :
s = 61.13 ft
So, the distance covered by the car before it comes to rest is 61.13 ft. Hence, this is the required solution.
A) Acceleration in part A:
B) Acceleration in part B:
C) Acceleration in part C:
Explanation:
A)
The picture of the problem is missing: find it in attachment.
The acceleration of a body is equal to the rate of change of its velocity:
where
v is the final velocity
u is the initial velocity
is the time it takes for the velocity to change from u to v
In part A of the race, we have:
u = 0
v = 5.5 m/s (estimate)
So the acceleration is
B)
In part B of the race, we have:
u = 5.5 m/s is the initial velocity (estimate)
v = 9.5 m/s is the final velocity (estimate)
is the time interval between the two points considered
Therefore, using the equation for the acceleration, we can find the acceleration in part B:
C)
In part C of the race, we have:
u = 9.5 m/s is the initial velocity (estimate)
v = 11 m/s is the final velocity (estimate)
is the time interval between the two points considered
And therefore, the acceleration in part C of the race is:
Learn more about acceleration:
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