I got it keep it bucks worth u this it tooooo muchhhhhhh
Explanation:
v=?, u=0, a=?, S=22m.
Using the formula, S=ut+½at²
22={0×5}+(½.a.5²)
22=½.a.5²
a=44/25 = 1.76m/s².
Therefore, net force = work done = ma = 48×1.76 = 84.48N.
therefore, power = work done/time = 84.48/5 = 16.896W.
hope this helps you.
Answer:
The required angular speed ω of an ultra-centrifuge is:
ω = 18074 rad/sec
Explanation:
Given that:
Radius = r = 1.8 cm
Acceleration due to g = a = 6.0 x 10⁵ g
Sol:
We know that
Angular Acceleration = Angular Radius x Speed²
a = r x ω ²
Putting the values
6 x 10⁵ g = 1.8 cm x ω ²
Converting 1.8 cm to 0.018 m, also g = 9.8 ms⁻²
6 x 10⁵ x 9.8 = 0.018 x ω ²
ω ² = (6 x 10⁵ x 9.8) / 0.018
ω ² = 5880000 / 0.018
ω ² = 326666667
ω = 18074 rad/sec
It is possible, but very slim. The fish will move before the spear goes through its body because the fish will sense danger and feel it hit the water and automatically move
Initial kinetic energy = 0J (v=0 (rest))
Final kinetic energy = 1/2mv ²
Ek=1/2(9)(27 ²)
Ek=4.5(729)
Ek=3280.5
∆Energy=3280.5J
(As it starts from 0)
Work= ∆energy
So work =3280.5J
Answer=3300J (forth option)
