Answer:
Change in position of an object A vector quantity with unit of distance.
Explanation:
Where is the object going? Final - initial
Here is the correct answer of the given problem above.
Given that the basket has a mass of 5.5kg, the magnitude of the normal force if the basket is at rest on a ramp inclined above the horizontal is at 12 degrees. The solution is simple:
<span>Fn at rest = lmgl </span>
<span>= 5.5kg (9.80N/kg)
=</span><span> mgCos12degrees
Hope this answer helps. </span>
Looks like you simply substitute the length of the femur
Equilibrium force is the force that will keep the small
mass in place, hence no movement must be made. So we know that 32 N of force is
acted towards the positive direction so +32 N. Which is counteracted by 26 N
force so:
32 N – 26 N = 6 N (positive)
Since positive 6 is left, therefore this must be acted by
an equilibrant negative 6 N.
Answer:
<span>- 6 N </span>
Actual Mechanical Advantage(AMA) = Weight / Force
Here, Weight = 764 N
Force = 255 N
Substitute the values in to the expression,
AMA = 764 / 255
AMA = 2.99
After rounding-off to the nearest tenth value, it would be 3
Finally, option C would be your answer.
Hope this helps!
