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2 years ago

When I current is running through a coil of wire with an iron core what is created around the wire that is carrying the current?

2 answers:

4 0

B) A magnetic field is created around the wire.

This idea is one of the fundamental ideas of physics - an electric current has a magnetic field, whether it's moving through a wire or space.

lozanna [386]2 years ago

4 0

Answer:

B. A magnetic field

Explanation:

As per Oersted experimental study he observed that when a magnetic needle is placed around the wire then this magnetic needle will show the deflection

this deflection is due to magnetic force due to some external magnetic field

So when we place a current carrying wire near the magnetic needle then it will produce the magnetic field near the wire and hence it will show the deflection in it

so here we can say that current carrying wire will produce magnetic field in the region surrounding the wire

so correct answer will be

B. A magnetic field

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Given that the collision is elastic and glider 2 is initially at rest (v2,i =0), please use below Eqs. to explain why

Morgarella [4.7K]

Answer:

Explanation:

1 )

Put v2,i =0, in second equation

v2,f= (m2-m1)v2,i + 2m1v1,i/m1+m2

v2,f = 0 + 2m1v1,i/m1+m2

v2,f = 2m1v1,i/m1+m2

In this equation coefficient of v1,i is positive so v2,f and v1,i have the same sign.

2 )

Put m1 < m2 and v2,i =0 in first equation

v1,f= (m1-m2)v1,i + 2m2v2,1/m1+m2

v1,f= (m1-m2)v1,i

As m1-m2 is negative , v1f and v1i will have opposite sign.

3 )

Put m1 > m2 and v2,i =0 in first equation

v1,f= (m1-m2)v1,i + 2m2v2,1/m1+m2

v1,f= (m1-m2)v1,i

m1 - m2 is positive so v1f and v1i will have same sign.

4 )

Put m1 = m2 and v2,i =0 in first equation

v1,f= (m1-m2)v1,i

= 0 because m1 = m2

So glider 1 will stop because v1,f = 0 .

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2 years ago

If the mass of an object is 44 kilograms and its velocity is 10 meters per second east, how much Kinetic Energy does it have?

olya-2409 [2.1K]

Given: Mass m = 44 Kg; Velocity v = 10 m/s

Required: Kinetic energy K.E = ?

Formula: K.E = 1/2 mv²

K.E 1/2 (44 Kg)(10 m/s)²

K.E = 2,200 Kg.m²/s²

K.E = 2,200 J Answer is A

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2 years ago

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Answer:

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2 years ago

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How do you solve 0.004 dm + 0.12508 dm?

Effectus [21]

0.004 of something added to 0.12508 of the same thing
adds up to 0.12908 of it.

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2 years ago

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2 years ago