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jok3333 [9.3K]
3 years ago
15

When I current is running through a coil of wire with an iron core what is created around the wire that is carrying the current?

Physics
2 answers:
pentagon [3]3 years ago
4 0
B) A magnetic field is created around the wire.

This idea is one of the fundamental ideas of physics - an electric current has a magnetic field, whether it's moving through a wire or space. 
lozanna [386]3 years ago
4 0

Answer:

B. A magnetic field

Explanation:

As per Oersted experimental study he observed that when a magnetic needle is placed around the wire then this magnetic needle will show the deflection

this deflection is due to magnetic force due to some external magnetic field

So when we place a current carrying wire near the magnetic needle then it will produce the magnetic field near the wire and hence it will show the deflection in it

so here we can say that current carrying wire will produce magnetic field in the region surrounding the wire

so correct answer will be

B. A magnetic field

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The CEO, ellen misk, left her martian office but accidentally left a cylindricall can of coke (3.1 inches in diameter, 5.42 inch
iren2701 [21]

Answer:

Specific Gravity = 0.378

Explanation:

First, we will find the force exerted by the can on the table. This force will be equal to the weight of the can:

Pressure = Force/Area = Weight/Area

Weight = Pressure*Area

where,

Area = πdiameter²/4 = π[(3.1 in)(0.0254 m/1 in)]²/4 = 4.8 x 10⁻³ m²

Weight = (510 N/m²)(4.8 x 10⁻³ m²)

Weight = 2.48 N

Now, the weight is given as:

Weight = mg

2.48 N = m(9.8 m/s²)

m = (2.48 N)/(9.8 m/s²)

m = 0.25 kg

Now, we calculate volume of can:

Volume = (Area)(Height) = (4.8 x 10⁻³ m²)(5.42 in)(0.0254 m/1 in)

Volume = 6.6 x 10⁻⁴ m³

Hence, the density of can will be:

Density of Can = m/Volume = 0.25 kg/6.6 x 10⁻⁴ m³

Density of Can = 378.32 kg/m³

So, the specific gravity of Can will be:

Specific Gravity = Density of Can/Density of Water

Specific Gravity = (378.32 kg/m³)/(1000 kg/m³)

<u>Specific Gravity = 0.378</u>

8 0
3 years ago
A submarine is 58.8 m from a whale. The sub sends out a sonar ping to locate the whale. The speed of sound underwater is 1520 m/
MissTica

Answer:

0.08

Explanation:

this problem assume that both of whale and submarine are in rest position or in constant linier motion in same direction and same speed.

The sound will travel from Submarine to the whale and back again to submarine. so the time will be like this

t = 2d/v

t = 2*58.8/1520

t = 117.6/1520

t = 0.077368 s

t ≈ 0.08 s (less then 1 s)

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The pressure on the outside of the bottle is greater  than it was when he put the cap on.  If anything could get out of the bottlde, it would. But it can't . . . the cap is on too tight. So all the water and all the air has to stay inside, and anything that can get squished into a smaller space has to get squished into a smaller space.

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