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3 years ago

A proton is placed in an electric field of intensity 700 n/

1 answer:

8 0

F=ma
F=QE = 1.602e-19C*700N/C = 1.1214e-16N
1.1214e-16N = ma = 1.6726e-27kg * a
a = 6.702e10 m/s² along the direction of the field line

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3 years ago

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7nadin3 [17]

Answer:

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Explanation:

Given that,

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The vertical component of velocity is v sinθ

So, vertical component is given by :

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3 years ago