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4 years ago

The wasted energy in a charger is:

Physics

1 answer:

kirza4 [7]4 years ago

4 0

Thermal is the wasted energy in a charger

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What are meant by the statement relative density of gold are 19.3

Doss [256]

It means that 19.3g of gold is packed into 1cm^3.

7 0

3 years ago

a loop of area 0.100 m^2 is oriented at a 15.5 degree angle to a 0.500 T magnetic field. it rotates until it is at a 45.0 degree

valina [46]

Answer:

0.128

Explanation:

Credit to charlizebarth

8 0

3 years ago

Read 2 more answers

A tank, shaped like a cone has height 12 meter and base radius 1 meter. It is placed so that the circular part is upward. It is

Temka [501]

Answer:

376966.991 Joules

Explanation:

Given that :

the height = 12 m

Let assume the tank have a thickness = dh

The radius of the tank by using the concept of similar triangle is :

$\dfrac{1}{r} = \dfrac{12}{h}$

$r = \dfrac{h}{12}$

The area of the tank = $\mathbf{\pi r^2}$

The area of the tank = $\mathbf{\pi( \dfrac{h}{12})^2}$

The area of the tank = $\mathbf{ \dfrac{\pi}{144}h^2}$

The volume of the tank is = area × thickness

= $\mathbf{ \dfrac{\pi}{144}h^2 \ dh}$

Weight of the element = $\rho_ g * volume$

where;

$\rho_g$ = density of water ; which is given as 10000 N/m³

So;

Weight of the element = $\mathbf{ 10000 *\dfrac{\pi}{144}h^2 \ dh}$

Weight of the element = $\mathbf{69.44 \ \pi \ h^2 \ dh}$

However; the work required to pump this water = weight × height rise

where the height rise = 12 - h

the work required to pump this water = $\mathbf{69.44 \ \pi \ h^2 \ dh}$ (12 - h)

the work required to pump this water = $\mathbf{69.44 \pi (12h^2-h^3)dh}$

We can determine the total workdone by integrating the work required to pump this water

SO;

Workdone = $\mathbf{\int\limits^{12}_0 {69.44 \pi(12h^2-h^3)} dh}$

= $\mathbf{ 69.44 \pi \int\limits^{12}_0 {(12h^2-h^3)} dh}$

= $\mathbf{ 69.44 \pi[ \frac{12h^3}{3}- \frac{h^4}{4}]^{12}}_0} }$

= $\mathbf{69.44 \pi [ \frac{12^4}{3}-\frac{12^4}{4}]}$

= $\mathbf{69.44 \pi*12^4 [ \frac{4-3}{12}]}$

= $\mathbf{69.44 \pi*12^4 *\frac{1}{12}}$

= 376966.991 Joules

6 0

3 years ago

What is the relevant similarity in the following argument?

Tasya [4]

Your answer would be C

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3 years ago

What is the main difference between analog anddigital technology?a. Digital technology reproduces sound more faithfullythan anal

daser333 [38]

Answer:

Answer b)

Explanation:

The correct answer is that analog technology stores information as sound-waves, while digital technology stores it as strings of ones and zeroes. So pick answer b)

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3 years ago