Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g) From the balanced chemical equation, 2 moles of HCl is required to react with 1 mole of Zn Mass of Zn = 9.55 g Molar mass of Zinc = 65.41 g/mol Number of moles = mass / molar mass Moles of Zn = 9.55 / 65.41 = 0.146 mol Moles of HCl required = 2 x moles of Zn = 2 x 0.146 = 0.292 mol
Exothermic i guess because delta h is negative
Answer:
0.107 mole of SO2.
Explanation:
1 mole of a gas occupy 22.4 L at standard temperature and pressure (STP).
With the above information, we can simply calculate the number of mole of SO2 that will occupy 2.4 L at STP.
This can be obtained as follow:
22.4 L contains 1 mole of SO2.
Therefore, 2.4 L will contain = 2.4/22.4 = 0.107 mole of SO2.
Therefore, 0.107 mole of SO2 is present in 2.4 L at STP.
22.3 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.
To find the mass, the given data was,
Volume = 11.6 Liters
<h3>What is decomposition reaction?</h3>
A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.
In airbags, sodium azide decomposes to form sodium and nitrogen gas, which inflates the bag. The decomposition reaction is:
2 NaN₃ ⇒ 2 Na + 3 N₂
We can calculate the mass of NaN₃ needed to produce 11.6 L of N₂ at STP, using the following relations.
- At STP, 1 mole of N₂ occupies 22.4 L.
- The molar ratio of N₂ to NaN₃ is 3:2.
- The molar mass of NaN₃ is 65.01 g/mol.
Substituting all the known values to find the volume,
11.6 × ( 1 / 22.4) × ( 2/3) × ( 65.01 / 1)
= 22.4 g.
22.4 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.
Learn more about decomposition reaction,
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Answer: the percentage of acetic acid will be low.
Explanation: The major aim during titration of acids and bases is to determine the endpoint , that is exact point where the acid in the beaker changes colour, (in this case, pink )with an additional drop from the burette containing the base, since it is usually difficult to mark the equivalence point that tells us when all the substrate in the beaker has been neutralized completely with the buretted substance.
Overshooting the end point is an error which can occur when the person involved in the the titration accidently goes beyond this endpoint by adding too much of the substance(base) from the burette into the beaker missing the exact endpoint.
This implies that the person has added too much of the burreted liquid, ie the base than required , making the acid in the beaker to continue to react resulting to a lower concentration of the acid (acetic acid) with excess base.(NaOH)
