How many molecules are in 4.50 moles of H2O?
2 answers:
You might be interested in
Answer:
A, C and D are correct.
Explanation:
Hello.
In this case, since the relationship between the vapor pressure of a solution is directly proportional to the mole fraction of the solvent and the vapor pressure of the pure solvent as stated by the Raoult's law:
Since the solute is not volatile, the mole fraction of the solute is not taken into account for vapor pressure of the solution, therefore A is correct whereas B is incorrect.
Moreover, since the higher the vapor pressure, the weaker the intermolecular forces due to the fact that less more molecules are like to change from liquid to vapor and therefore more energy is required for such change, we can evidence that both C and D are correct.
Best regards.
Explanation:
The given reaction is as follows.
As it is known that number of moles equal mass divided by molar mass. Molar mass of methane is 16 g/mol.
Hence, No. of moles =
=
= 0.493 mol
Molar mass of oxygen is 32 g/mol.
Hence, its number of moles =
=
= 0.45 mol
As, it is shown from the reaction that 1 mole of methane needs 2 mole of oxygen.
Therefore, 0.493 mol of methane needs equals 0.9 moles of oxygen.
As there is only 0.45 moles of oxygen for the reaction. So, it means that oxygen is the limiting reagent.
Hence, for 0.45 moles of oxygen, methane required is as follows.
= 0.225 moles
So, 0.225 moles of methane is equal to = 3.6 g
As, 3.6 g of methane reacts with oxygen. Therefore, amount of methane remains is calculated as follows.
(7.9 g - 3.6 g) = 4.3 g
Thus, we can conclude that the minimum mass of methane that could be left over by the chemical reaction is 4.3 g.