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3 years ago

How many milliliters of 5.50 m hcl(aq) are required to react with 9.55 g of zn(s)?

1 answer:

6 0

Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g) From the balanced chemical equation, 2 moles of HCl is required to react with 1 mole of Zn Mass of Zn = 9.55 g Molar mass of Zinc = 65.41 g/mol Number of moles = mass / molar mass Moles of Zn = 9.55 / 65.41 = 0.146 mol Moles of HCl required = 2 x moles of Zn = 2 x 0.146 = 0.292 mol

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4 years ago

Please Explain. Why does salt water boil at a lower temperature than tap water?

nexus9112 [7]

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3 years ago

As a chemist for an agricultural products company, you have just developed a new herbicide,"Herbigon," that you think has the po

Ganezh [65]

Answer:

pH = 2.03

Explanation:

The pH can be calculated using the following equation:

$pH = -log [H_{3}O^{+}]$ (1)

The concentration of H₃O⁺ is calculated using the dissociation constant of the next reaction:

CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺

1.00 M

$K_{a} = \frac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}$

Solving the above equation for H₃O⁺, we have:

$[H_{3}O^{+}] = \frac{Ka*[CH_{3}COOH]}{[CH_{3}COO^{-}]}$ (2)

The dissociation constant is equal to:

$pKa = -log(Ka) \rightarrow Ka = 10^{-pKa} = 10^{-4.76} = 1.74 \cdot 10^{-5}$

Now, by solving the equation of the solubility product for Herbigon, we can find [CH₃COO⁻]:

CH₃COOX ⇄ CH₃COO⁻ + X⁺

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$K_{sp} = [CH_{3}COO^{-}][X^{+}]$

$[CH_{3}COO^{-}] = \frac{K_{sp}}{[X^{+}]} = \frac{9.40 \cdot 10^{-6}}{5.00 \cdot 10^{-3}} = 1.88 \cdot 10^{-3} M$

By entering the values of [CH₃COO⁻] and Ka, into equation (2) we can calculate [H₃O⁺]:

$[H_{3}O^{+}] = \frac{1.74 \cdot 10^{-5}*[1.00]}{[1.88 \cdot 10^{-3}]} = 9.26 \cdot 10^{-3} M$

Hence, the pH is:

$pH = -log [H_{3}O^{+}] = -log [9.26 \cdot 10^{-3}] = 2.03$

Therefore, the pH must be 2.03 to yield a solution in which the concentration of X⁺ is 5.00x10⁻³M.

I hope it helps you!

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4 years ago

You are on vacation with your family up in the mountains. your friend is on vacation near the equator by the ocean.Explain which

kirill115 [55]

Answer:

option d is right

Explanation:

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3 years ago