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sergeinik [125]

3 years ago

13

Given f(x)= -x^2+3x-4 and g(x)=2/3x +5 find f(g(-9))

1 answer:

scZoUnD [109]3 years ago

6 0

Answer:

0

Step-by-step explanation:

First, you plug -9 into g(x) and you get g(-9) = - 1. After that, you solve f(-1), which you then reach the solution of 0 by solving.

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PLEASE HELP!! I WILL AWARD BRAINLIEST AND 50 POINTS!!!!!!!!!!!!!!!!!!!!!! For the given picture: a) List all of the triangles th

PIT_PIT [208]

Answer:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB

Step-by-step explanation:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB

6 0

3 years ago

Graph the function. ( Look at the picture for the problem and graph. Need help and please only answer if you know the right answ

aliya0001 [1]

Answer:

there is a website called desmos and you can type all of that in and it can graph it, hope that helps(: and its free

5 0

2 years ago

The diameter of a circle is 14 inches, Eind the circumference and area. Use<br> Find<br> 22 for it.

snow_lady [41]

Answer:

Step-by-step explanation:

If diameter is 14 inches radius = d/2 = 14/2 = 7 inches

Circumference = 2 pi R = 2 × 22/7 × 7

= 44 inches

Area = pi R square = 22/7 × (7)^2

=22/7 × 49

= 154 inches

Hope this helps

7 0

3 years ago

What are the factors of the square root of 329

Andru [333]

Answer: $x=-\dfrac{3}{2}, 7$

Step-by-step explanation:

$2x^2-10x-26=x-5$

$2x^2-10x-26-x+5=0$ Move all terms to one side

$2x^2-11x-21=0$ Simplify $2{x}^{2}-10x-26-x+5$

$2x^2+3x-14x-21=0$ Split the second term

$x(2x+3)-7(2x+3)=0$ Factor out common terms in the first two terms, then in the last two terms.

$(2x+3)(x-7)=0$ Factor out the common term $2x+3$

$x=-\dfrac{3}{2}, 7$

5 0

2 years ago

Read 2 more answers

EMERGENCY (NEED HEP NOW!!!)

diamong [38]

Answer:

x=-2.25,y=-2.25

Step-by-step explanation:

The given system is

$4x - y = - 9 \\ 3x - 3y = 0$

We want to solve the system for x and y that makes the system true.

Let us multiply the first equation by 3 while maintaining the second equation:

$12x -3 y = - 27 \\ 3x - 3y = 0$

Subtract the current second equation from the first one.

$12x = - 27$

Divide through by 12:

$x = - \frac{27}{12} = - 2.25$

From the second equation we have:

$3x = 3y$

This implies that:

$x = y = - 2.25$

8 0

3 years ago