Answer:
[H⁺] = 0.00013 M
[OH⁻] = 7.7 × 10⁻¹¹ M
Explanation:
Step 1: Calculate the concentration of H⁺ ions
HCl is a strong acid that dissociates according to the following equation.
HCl ⇒ H⁺ + Cl⁻
The molar ratio of HCl to H⁺ is 1:1. The concentration of H⁺ is 1/1 × 0.00013 M = 0.00013 M.
Step 2: Calculate the concentration of OH⁻ ions
We will use the ionic product of water equation.
Kw = 10⁻¹⁴ = [H⁺] × [OH⁻]
[OH⁻] = 10⁻¹⁴/[H⁺] = 10⁻¹⁴/0.00013 = 7.7 × 10⁻¹¹ M
Molar mass helium gas :
He = 4.0 g/mol
number of moles: 3.75 / 4.0 => 0.9375 moles
1 mole ------ 22.4 ( at STP)
0.9375 ------ ?
volume = 0.9375 x 22.4 / 1
Volume = 21 / 1
Volume = 21 L
hope this helps!
There are 680,000 microliters in 0.68 liters.
Ionic molecules have higher boiling point than covalent molecules.
So that leaves Na2SO4 and NaCl.
The ionic molecule with higher charge will have higher boiling point.
Na2SO4 have ions with charge +-2.
NaCl have ions with charge +-1.
So the answer is C.
Answer:
The answer to your question is 1.83 x 10²⁵ particles
Explanation:
Data
particles of H₂O = ?
mass of H₂O = 546 g
Process
1.- Calculate the molar mass of Water
Molar mass = (2 x 1) + (1 x 16)
= 2 + 16
= 18 g
2.- Use proportions to find the number of particles. Use Avogadro's number.
18 g ---------------- 6.023 x 10²³ particles
546 g --------------- x
x = (546 x 6.023 x 10²³) / 18
3.- Simplification
x = 3.289 x 10²⁶ / 18
4.- Result
x = 1.83 x 10²⁵ particles
