Answer:
32 yd
Explanation:
hope this helps :) A P E X
101.59164 Kilopascal (kPa)
The H+ in a solution that has a Ph of 8.73 is calculate as follows
Ph is always = - log (H+)
H+ = 10^-Ph
H+ is therefore = 10 ^- 8.73
H+ = 1.86 x10^-9 M
Answer:
Total number of ATP molecules generated from a 32-carbon fatty acid = 206 ATP molecules
Explanation:
A 32 carbon fatty acid which undergoes complete beta-oxidation assuming that the fatty acid is fully saturated will pass through the beta-oxidation cycle 14 times to produce the following:
15 molecules of acetylCoA, 14 molecules of FADH₂, and 14 molecules of NADH.
Each of the 15 acetylCoA molecules can be further oxidized in the citric acid cycle to yield the following: 15 × 3 NADH; 15 × 1 FADH₂, and 15 ATP molecules from the substrate level phosphorylation occuring at the succinylCoA synthetase catalyzed-reaction.
Total FADH₂ produced = 15 + 14 = 29 molecules of FADH₂
Total NADH produced = 45 + 14 = 59 molecules of NADH
The FADH₂ and NADH will each donate a pair of electrons to the electron transfer flavoprotein and mitochondrial NADH dehydrogenase respectively of the electron transport chain, and about 1.5 and 2.5 molecules of ATP are generated respectively when these electrons are transfered to molecular oxygen.
Thus, number of molecules of ATP generated by 29 molecules of FADH₂ = 1.5 × 29 = 43.5 molecules of ATP.
Number of molecules of ATP generated by 59 molecules of NADH = 2.5 × 59 = 147.5
Sum of ATP generated from FADH₂ and NADH = 43.5 + 147.5 = 191 ATP molecules
Total number of ATP molecules generated = 191 + 15 = 206 ATP molecules
Total number of ATP molecules generated from a 32-carbon fatty acid = 206 ATP molecules
Answer:
Therefore, 107 ml of 2.5% w/v chlorpromazine hydrochloride injection and 393 ml of 0.9% w/v sodium chloride injection are needed to prepare 500 mL of a 0.3% w/v chlorpromazine hydrochloride injection
Explanation:
The method to be used in determining the proportions of each component to be used to get the desired mixture is known as alligation alternate.
Alligation alternate is a method by which to calculate the number of parts of two or more components of a given strength when they are to be mixed to a desired strength. The difference between the strength of the stronger component and the desired strength indicates the number of parts of the weaker component to be used and the difference between the desired strength and the strength of the weaker component indicates the number of parts of the stronger to be used.
Desired strength = 0.3%
Number of parts of 2.5% w/v chlorpromazine hydrochloride injection to be used = 0.9 - 0.3 = 0.6 parts
Number of parts of 0.9% w/v sodium chloride injection to be used = 2.5 - 0.3 = 2.2 parts
Total parts = 2.8 parts
2.8 parts of 0.3% w/v chlorpromazine hydrochloride injection = 500 ml
0.6 parts of 2.5% w/v chlorpromazine hydrochloride injection = 0.6 * 500 ml/2.8 = 107 ml of 2.5% w/v chlorpromazine hydrochloride injection
2.2 parts of 0.9% w/v sodium chloride injection = 2.2 * 500 / 2.8 = 393 ml of 0.9% w/v sodium chloride injection
Therefore, 107 ml of 2.5% w/v chlorpromazine hydrochloride injection and 393 ml of 0.9% w/v sodium chloride injection are needed to prepare 500 mL of a 0.3% w/v chlorpromazine hydrochloride injection