1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alika [10]
3 years ago
5

Why do real gases not behave exactly like ideal gases?

Chemistry
2 answers:
solniwko [45]3 years ago
5 0

Real gas particles have significant volume

Real gas particles have more complex interactions than ideal gas particles

tia_tia [17]3 years ago
3 0

The answer is;

  1. Real gas particles have significant volume
  2. Real gas particles have more complex interactions than ideal gas particles

When using the ideal gas equation (PV= nRT)particular assumptions are made. That the molecules of the gas occupy negligible space and that the molecules only interact through elastic collision. However, the molecules of real gas have a finite volume and they interact also through intermolecular forces (such as in partially-charged molecules).

You might be interested in
Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in
Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is  2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\   \frac{m_{S} }{m_{O} }= 2

Let us express it as

SO_{\frac{m_{S} }{m_{O} }} = 2

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\   \frac{m_{S} }{m_{O} }= 1

Let us express it as

SO_2_{\frac{m_{S} }{m_{O} }}= 1

Now, for the ratio of both the above-calculated ratios,

\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}

The required ratio is 2:1

3 0
3 years ago
What aqueous solution has the highest boiling point at standard pressure? A) 1.0 M KCl(aq) B) 1.0 M CaCl2(aq) C) 2.0 M KCl(aq) D
Lapatulllka [165]
The increase in the boiling point of a solvent is a colligative property.


That means that the increase in the boling point will be related to the number of particles (molecules or ions) present in the solution.


The higher the number of particles (molecules or ions) the higher the increase in the boiling point.


All the aqueous solutions presented are electrolytes, i.e. the solutes are ionic compounds.


Then, you have to compare the number of ions that you have in each solution.


A) 1.0 M KCl ---> 1.0 M K+     +      1.0 MCl-    = 2 moles of particles / liter


B) 1.0 M CaCl2 --> 1.0M Ca(2+)      +      1.0M * 2 Cl (-)    = 3 moles of particle / liter


C) 2.0M KCl ---> 2.0 M K+      +      2.0 M Cl-  = 4 moles of particle / liter


D) 2.0 M CaCl2 ----> 2.0 M Ca (2+)      + 2.0M * 2 Cl (-)  = 6 moles of particle / liter.


Then, the solution 2.0M CaCl2(aq) has the highest increase in the boiling point.


Answer: option D) 2.0 M Ca Cl2(aq)
5 0
3 years ago
a factor of 8, it means that A is now only 1/8 of its original concentration. A first order reaction, where A → products, has a
Trava [24]

Answer:

It takes 1.32x10⁻⁷s for the concentration of A to fall by a factor of 8

Explanation:

The equation that represents a first-order kinetics is:

Ln ([A] / [A]₀] = -kt

<em>Where [A] is actual concentration, [A]₀ is initial concentration, K is rate constant (For the given problem, 1.57x10⁷s⁻¹ and t is time.</em>

<em />

As you want the time when you have [A] in a factor of 8 = [A] / [A]₀ = 1/8

Replacing:

Ln ([A] / [A]₀] = -kt

Ln (1/8) = -1.57x10⁷s⁻¹*t

t = 1.32x10⁻⁷s

<h3>It takes 1.32x10⁻⁷s for the concentration of A to fall by a factor of 8</h3>

4 0
3 years ago
he Punnett square shows the possible genotype combinations for the offspring of two parents. What are the genotypes of the paren
Delicious77 [7]
The genotypes of the parents are Gg and Gg.
7 0
3 years ago
Read 2 more answers
Information about how a chemical reacts under high pressure can be found in the ""reactivity"" section of a msds. True or false?
dezoksy [38]

Information about how a chemical reacts under high pressure can be found in the "reactivity" section of a MSDS: True.

<h3>What is MSDS?</h3>

MSDS is an abbreviation for Material Safety Data Sheet and it can be defined as a text-based document which is designed and developed to provide more information with respect to the chemical and physical properties of an equipment, chemical compound, or substance, based on the following:

  • Reactivity
  • Flammability
  • Temperature
  • Radioactivity

In this context, we can infer and logically deduce that it is true that the information about how a chemical react would under high pressure can be found in the "reactivity" section of a Material Safety Data Sheet (MSDS).

Read more on Material Safety Data Sheet here: brainly.com/question/3282390

#SPJ1

8 0
2 years ago
Other questions:
  • Many manufacturing processes involve chemical reactions that reach equilibrium. Why would chemists adjust conditions to favor th
    5·2 answers
  • How many electrons are transferred during the formation of one molecule of al2o3?
    8·1 answer
  • PLEASE HELP!! URGENT!!
    5·1 answer
  • I don't know how to do this, pls help!
    8·2 answers
  • What would happen to earth's orbit around the sun if there were gravity
    6·1 answer
  • I need help ASAP answer must be correct really important test!!!! Will give brainlest☺️☺️☺️
    10·2 answers
  • Solid at room temperature. They are used in making computers and electronic devices. Have properties of both metals and nonmetal
    7·2 answers
  • Please help :) ill mark you as the brainiest hope you have a good day
    14·1 answer
  • Which scientist invented the first simple Microscope ?
    8·1 answer
  • How do ecosystems respond to natural disasters such as fires and floods?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!