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Tems11 [23]
2 years ago
11

The diagram shows steps and structures involved in protein production

Chemistry
2 answers:
irinina [24]2 years ago
7 0
A ribosome
a ribosome transcribes mRna
Amiraneli [1.4K]2 years ago
7 0

Answer:

Hi dollface! The answer is the ribosome!

Explanation: Took the test!

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Which pair shares the same empirical formula?
ZanzabumX [31]

Answer:- 3. CH_3 and C_2H_6

Explanations:- An empirical formula is the simplest whole number ratio of atoms of each element present in the molecule/compound.

For example, the molecular formula of benzene is C_6H_6 . The ratio of C to H in it is 6:6 that could be simplified to 1:1. So, an empirical formula of benzene is CH.

In the first pair, the ratio of C to H in first molecule is 2:4 that could be simplified to 1:2 and  the empirical formula is CH_2 . In second molecule the ratio of C to H is 6:6 and it could be simplified to 1:1. and the empirical formula is CH. Empirical formulas are different for both the molecules of first pair and so it is not the right choice.

In second pair, C to H ratio in first molecule is 1:2, so the empirical formula is CH_2 . The C to H ratio for second molecule is 1:4, so the empirical formula is CH_4 . Here also, the empirical formulas are not same and hence it is also not the right choice.

In third pair, C to H ratio in first molecule is 1:3, so the empirical formula is CH_3 . In second molecule the C to H ratio is 2:6 and it is simplified to 1:3. So, the empirical formula for this one is also CH_3 . Hence. this is the correct choice.

In fourth pair, first molecule empirical formula is CH. Second molecule has 2:4 that is 1:2 mole ratio of C to H and so its empirical formula is CH_2 . As the empirical formulas are different, it is not the right choice.

So, the only and only correct pair is the third one. 3. CH_3 and C_2H_6

4 0
3 years ago
Read 2 more answers
What is the molarity of a stock solution if 60 mL were used to make 150 ml<br>of a .5M solution? ​
olga2289 [7]

The molarity of the stock solution is 1.25 M.

<u>Explanation:</u>

We have to find the molarity of the stock solution using the law of volumetric analysis as,

V1M1 = V2M2

V1 = 150 ml

M1 = 0.5 M

V2 = 60 ml

M2 = ?

The above equation can be rearranged to get M2 as,

M2 = $\frac{V1M1}{V2}

Plugin the values as,

M2 = $\frac{150 \times 0.5}{60}

       = 1.25 M

So the molarity of the stock solution is 1.25 M.

4 0
3 years ago
Name the seventh inner transition metal in period 6
vladimir1956 [14]

Answer:

<h3>Don't know..</h3>

follow me and mark me brainliest

8 0
3 years ago
Examine this model of an amino acid that has formed a peptide bond. What process is illustrated in this drawing? 
disa [49]
The condensation polymerization process is being demonstrated, where two molecules come together to form a larger molecule while releasing a smaller molecule, in this case water.
8 0
3 years ago
Read 2 more answers
Nitroglycerine decomposes violently according to the chemical equation below. What mass of carbon dioxide gas is produced from t
AveGali [126]

Answer : The mass of CO_2  produced is, 7.74 grams

Solution : Given,

Mass of C_3H_5(NO_3)_3 = 13.3 g

Molar mass of C_3H_5(NO_3)_3 = 227 g/mole

Molar mass of CO_2 = 44 g/mole

First we have to calculate the moles of C_3H_5(NO_3)_3.

\text{ Moles of }C_3H_5(NO_3)_3=\frac{\text{ Mass of }C_3H_5(NO_3)_3}{\text{ Molar mass of }C_3H_5(NO_3)_3}=\frac{13.3g}{227g/mole}=0.0586moles

Now we have to calculate the moles of CO_2

The balanced chemical reaction is,

4C_3H_5(NO_3)_3\rightarrow 12CO_2(g)+6N_2(g)+10H_2O(g)+O_2(g)

From the reaction, we conclude that

As, 4 mole of C_3H_5(NO_3)_3 react to give 12 mole of CO_2

So, 0.0586 moles of C_3H_5(NO_3)_3 react to give 0.0586\times \frac{12}{4}=0.176 moles of CO_2

Now we have to calculate the mass of CO_2

\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2

\text{ Mass of }CO_2=(0.176moles)\times (44g/mole)=7.74g

Thus, the mass of CO_2  produced is, 7.74 grams

4 0
3 years ago
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