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kolbaska11 [484]
3 years ago
11

What is the value of δg°' (or, to put it another way, the cost) when 2nadp+ and 2h2o are converted to 2nadph plus 2h+ plus o2?

Chemistry
2 answers:
Nikolay [14]3 years ago
8 0

The chemical reaction is given as:

2NaDP^{+} +2H_{2}O\rightarrow 2NaDPH+2H^{+}+O_{2}

Here, oxygen is oxidised and NaDP^{+} is reduced. Thus, redox reaction occurs.

For cell reaction, \Delta G^{o} = -nFE^{o}_{cell}          (2)

where, \Delta G^{o} = standard state free energy

n= number of electrons

F= Faraday constant (96485.33 C/mol)

E^{o}_{cell} = cell potential

Substitute the value of number of electrons i.e. 2, Faraday constant and cell potential in the formula to determine the value of  \Delta G^{o}.

Now, calculate the value of cell potential

E^{o}_{cell} = E^{o}_{cathode}- E^{o}_{anode}           (1)

E^{o}_{cathode} = -0.324 V (standard reduction potential of NaDP^{+})

E^{o}_{anode} = 1.23 V (standard reduction potential of O_{2})

Put the above values in formula (1), we get:

E^{o}_{cell} = -0.324 V-1.23 V

= -1.554 V

Now, substitute above value in formula (2)

\Delta G^{o} = -2\times 96485.33 C/mol \times(-1.554 V)  

= 299876.40564 CV/mol

Since, one coulomb volt is equal to one joule.

Thus, value of \Delta G^{o} is equal to 299876.40564 J/mol or 299.87640564 kJ/mol








svp [43]3 years ago
4 0
The answer is 104.9, i dont know how though
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What volume of lead (of density 11.3 g/cm3) has the same mass as 330 cm3 of a piece of redwood (of density 0.38 g/cm3)?
zimovet [89]

Answer:

The sample of lead has a volume of 11.1 cm³

Explanation:

<u>Step 1:</u> Data given

x cm³ lead has a density of 11.3 g/cm³

it has the same mass as 330cm³ of a piece of redwood with density 0.38g/cm³

<u>Step 2</u>: Calculate mass of the piece of redwood

Density = mass/volume

mass = density * volume

Mass of the piece of redwood = 0.38 g/cm³ * 330cm³ = 125.4 grams

Since the sample of lead has the same mass, it also has a mass of 125.4 grams

<u>Step 3</u>: Calculate volume of the lead

Density = mass/ volume

Volume = mass/ density

Volume of lead = 125.4g / 11.3g/cm³ = 11.097 cm³≈11.1 cm³

The sample of lead has a volume of 11.1 cm³

3 0
3 years ago
Please leave workings as well
yulyashka [42]

Answer:

15g

Explanation:

The equation for the reaction is given below:

CaO + SO2 —> CaSO3

Molar Mass of CaO = 40 + 16 = 56g/mol

Molar Mass of CaSO3 = 40 + 32 + (16x3) = 40 + 32 + 48 = 120g/mol

From the equation,

56g of CaO produced 120g of CaSO3.

Therefore, 7g of CaO will produce = (7 x 120)/56 = 15g of CaSO3

Therefore, 15g of CaSO3 is produce

5 0
3 years ago
The process by which water vapor changes to liquid water is called
andre [41]
When water is turned into vapor (a gas), that is called evaporation.

Hope this helps. :)
6 0
3 years ago
Can someone help me out please ? I am very stuck here
Alex17521 [72]
Hey there!

<span>Atomic Masses :
</span>
H = <span>1.00794  a.m.u
N = </span><span>14.0067  a.m.u
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Therefore:

HNO3 = </span>1.00794 + 14.0067 + ( 15.9994 * 3 ) =>  <span>63.0128 g/mol</span>
7 0
3 years ago
I need the correct answers
bogdanovich [222]

Answer:

Acids: Tastes Sour

Has a ph less than 7

Base: Bitter

Has a ph greater than 7

slippery

Acid&Base: Conducts electricity

4 0
3 years ago
Read 2 more answers
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