Answer:
27
Step-by-step explanation:
9 is not a perfect cube.
18 is not a perfect cube.
27 is a perfect cube.
∛27 = 3
36 is not a perfect cube.
Answer:
BD = 8.8
Step-by-step explanation:
You have a right triangle.
The hypotenuse is BD
The side opposite the 27o angle is 4
Sin(27) = opposite / hypotenuse.
Sin(27) = 0.45399
opposite = 4
hypotenuse = ?
0.45399 = 4/hypotenuse
BD = 4/0.45399
BD = 8.811
The answer is 8.8
The answer is 2/16 if you do the math with the numerators only.
1. Let a and b be coefficients such that
Combining the fractions on the right gives
so that
2. a. The given ODE is separable as
Using the result of part (1), integrating both sides gives
Given that y = 1 when x = 1, we find
so the particular solution to the ODE is
We can solve this explicitly for y :
![\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|](https://tex.z-dn.net/?f=%5Cln%7Cy%7C%20%3D%20%5Cln%5Cleft%7C%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%5Cright%7C)
![\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%7D)
2. b. When x = 9, we get
![y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B45%7D%7B21%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B15%7D7%7D%20%5Capprox%20%5Cboxed%7B1.29%7D)
Answer:
1
0
(
3
+
4
)
Step-by-step explanation:
