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BartSMP [9]
4 years ago
6

A substance has a melting point of 0��c and a boiling point of 100��c. the substance is most likly?

Chemistry
2 answers:
faltersainse [42]4 years ago
4 0
Water, because if water reaches to 0°C, it becomes ice (solid). If 100° C, it becomes steam (gas).
solniwko [45]4 years ago
3 0

Answer:

Water

Explanation:

The answer is water.  Since the it falls into both of these categories, the answer is water.

Answer:  Water

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Which type of precipitation is shown in the diagram below? How does this precipitation form?
Kisachek [45]

Answer:

precipitation means water droplets may grow as a result of additional condensation of water vapor when the particles collide. If enough collisions occur to produce a droplet with a fall velocity which exceeds the cloud updraft speed, then it will fall out of the cloud as precipitation.

Explanation:

i knew this alr

3 0
2 years ago
Assuming that a sample of ethanol weighs 560 grams. What is the mass of hydrogen in grams for the sample?
Novosadov [1.4K]

Answer:

BRO WHAT THEY ANSWER TO UR BUT NOT MINE OK

Explanation: I THINK THE ASNSWER IS C BUT NOT SURE.... HOPE IT HELPS

6 0
3 years ago
In determining nuclear binding energy, what is Einstein's equation used to do?
natita [175]
Basically this is used in calculating the nuclear binding energy by converting the mass defect (calculated first) to energy and if we recall, Einstein's equation E=mc2 is the perfection equation to use because E=mc2 in which E represents units of energy, m represents units of mass, and c 2 is the speed of light squared. 
3 0
4 years ago
What is the name of group 5a
EastWind [94]

Answer:

It is called <em>Pnictogens</em><em>.</em>

Explanation:

This word is fro a greek word called <em>p</em><em>n</em><em>i</em><em>g</em><em>e</em><em>i</em><em>n</em><em> </em>which means <em>c</em><em>h</em><em>o</em><em>k</em><em>i</em><em>n</em><em>g</em><em> </em>due to a choking property of <em>n</em><em>i</em><em>t</em><em>r</em><em>o</em><em>g</em><em>e</em><em>n</em><em> </em><em>g</em><em>a</em><em>s</em><em> </em>when opposed to air with (oxygen).

5 0
3 years ago
If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated
Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution

\Delta T^o = freezing point of water

i = Van't Hoff factor

K_f = freezing point constant

m = molality

w_b = mass of solute

w_a = mass of solvent

M_b = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0
4 years ago
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