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Tanya [424]
3 years ago
13

How many grams of KO2 are needed to form 8.0 g of O2?

Chemistry
2 answers:
dem82 [27]3 years ago
4 0
Using the atomic weights, K = 39, O=16 so KO2= 39+32=71. So K=39/71= 0.549 of KO2 and O2=32=0.45KO2 and O2=8g and 0.45KO2=8g so KO2=8/0.45=17.77g. So to check, K=0.549 x 17.77g=9.76 and so K+O2= 9.76+8g=17.76.
zubka84 [21]3 years ago
4 0

23.43 grams of KO₂ is needed to form 8.0 g of O₂

<h3>Further explanation</h3>

Stochiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculations of volume, mass, number, which are related to the number of actions, molecules, elements, etc.

In chemical calculations, the reaction can be determined, the number of substances that can be expressed in units of mass, volume, mole, or determine a chemical formula, for example, the substance level or molecular formula of the hydrate.

The reaction equation is the chemical formula of reagents and product substances

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction equation there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

The reaction between potassium superoxide, KO₂, and CO₂, to get O₂, is usually used by rescue teams in the form of breathing equipment

4KO₂ + 2CO₂ → 2K₂CO₃ + 3O₂

From the above equation the reaction shows that for every 4 moles of KO₂ you will get 3 moles of O₂, or a ratio of moles of KO₂: moles of O₂ = 4: 3

If we want to get 8 grams of O₂, then the number of moles of O₂ becomes:

mole O₂ = gram: molecular mass of O₂

mol O₂ = 8 gram: 32

mol O₂ = 0.25

so the number of KO₂ moles needed: (we use a ratio of KO₂ and O₂ moles)

mol KO₂ = 4/3 x mol O₂

KO KO2 = 4/3 x 0.25

mol KO2 = 0.33 mol

So the number of grams of KO₂ needed

gram KO₂ = mol x molecular mass KO₂

gram KO₂ = 0.33 x 71

gram KO₂ = 23.43

<h3>Learn more</h3>

The mass of one mole of raindrops

brainly.com/question/5233234

moles of NaOH

brainly.com/question/4283309

moles of water you can produce

brainly.com/question/1405182

Keywords: mole, KO₂, O₂, breathing equipment

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Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.
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If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

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The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

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More about the ideal gas equation link is given below.

brainly.com/question/4147359

#SPJ1

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