Answer:
1.524
Step-by-step explanation:
Answer:
-11.1 and up
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.
The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.
Circumscribed circle always passes through the vertices of the triangle.
Inscribed circle is always tangent to the triangle's sides.
In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.
Answer: (2,1)
Step-by-step explanation:
The two equations given are:
y = 3 -x
y = x - 1
The question is asking to determine the point of intersection for two linear functions aka two lines.
Step #1: Both functions must be in slope intercept form which is y = mx+b. In this case, this step can be skipped because both functions are in slope form. At an intersection, x and y must have the same value for each equation. This means that the equations are equal to each other. Therefore, we can set both equations equal to each other to solve for x.
- Add x to both sides to get 2x - 1 = 3
- Add 1 to both sides to get 2x = 4
- Divide both sides by 2 to get x = 2
Step #2: We found the x-coordinate, but we need to find the y-coordinate. We know that the x-coordinate is 2, so substitute the number 2 into any of the given equations. So, either into y = 3 - x or y = x - 1.
The point of intersection is (2,1).
Hope this helps ^_^