What is the missing side and what is the answer rounded to the nearest tenth?

Nonamiya [84]

$16. \ \ V= \pi r^2h \ \to \ r^2= \cfrac{V}{ \pi h} \ \to \ \boxed{r= \sqrt{ \frac{V}{ \pi h} } } \\ \\ \\ 17.\ \ d= \frac{1}{2} at^2 \ \to \ 2d= at^2 \ \to \ t^2= \cfrac{2d}{a} \ \to \ \boxed{t= \sqrt{\frac{2d}{a}}} \\ \\ \\ 18. \ \ S=180(n-2) \ \to \ \cfrac{S}{180}=n-2 \ \to \ \boxed{n= \frac{S}{180}+2 }$

6 0

4 years ago

What do I do I can't understand it my teacher stupid

denpristay [2]

Make them all fractions over 4, so 3 would be 12/4, and 1 1/4 would be 5/4 so add them together
12/4+5/4= 17/4 then divide by 4 to reduce it, to get 4 1/4

5 0

3 years ago

plz help me suzy spent 6 7/8 days working on her English paper 3 1/6 days on her science project and 1 1/2 days studying for her

malfutka [58]

Answer:

English time + Math Time = 6 7/8 + 1 4/8 = 7 7/8+4/8 = 8 3/8

8 3/8 - Science time = difference = 8 3/8- 3 1/6 = 5 5/24

She spent 5 5/24 days more on her English and Math test than Science

Step-by-step explanation:

5 0

4 years ago

SOMEONE PLZZZ HELP ME PLZZZZZZ

qaws [65]

Answer:

hiii

Step-by-step explanation:

=-8

7 0

3 years ago

Read 2 more answers

In triangle RST, m∠R > m∠S + m∠T. Which must be true of triangle RST? Check all that apply.

solmaris [256]

Answer:

1. m∠R > 90°

2. m∠S + m∠T < 90°

4. m∠R > m∠T

5. m∠R > m∠S

Step-by-step explanation:

<h3>General strategy</h3>

prove the statement starting from known facts, or
disprove the statement by finding a counterexample

Helpful fact: Recall that the Triangle Sum Theorem states that m∠R + m∠S + m∠T = 180°.

Option 1. m∠R > 90°

Start with m∠R > m∠S + m∠T.

Adding m∠R to both sides of the inequality...

m∠R + m∠R > m∠R + m∠S + m∠T

There are two things to note here:

The left side of this inequality is 2*m∠R
The right side of the inequality is exactly equal to the Triangle Sum Theorem expression

2* m∠R > 180°

Dividing both sides of the inequality by 2...

m∠R > 90°

So, the first option must be true.

Option 2. m∠S + m∠T < 90°

Start with m∠R > m∠S + m∠T.

Adding (m∠S + m∠T) to both sides of the inequality...

m∠R + (m∠S + m∠T) > m∠S + m∠T + (m∠S + m∠T)

There are two things to note here:

The left side of this inequality is exactly equal to the Triangle Sum Theorem expression
The right side of the inequality is 2*(m∠S+m∠T)

Substituting

180° > 2* (m∠S+m∠T)

Dividing both sides of the inequality by 2...

90° > m∠S+m∠T

So, the second option must be true.

Option 3. m∠S = m∠T

Not necessarily. While m∠S could equal m∠T, it doesn't have to.

Example 1: m∠S = m∠T = 10°; By the triangle sum Theorem, m∠R = 160°, and the angles satisfy the original inequality.

Example 2: m∠S = 15°, and m∠T = 10°; By the triangle sum Theorem, m∠R = 155°, and the angles still satisfy the original inequality.

So, option 3 does NOT have to be true.

Option 4. m∠R > m∠T

Start with the fact that ∠S is an angle of a triangle, so m∠S cannot be zero or negative, and thus m∠S > 0.

Add m∠T to both sides.

(m∠S) + m∠T > (0) + m∠T

m∠S + m∠T > m∠T

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠T.

So, option 4 must be true.

Option 5. m∠R > m∠S

Start with the fact that ∠T is an angle of a triangle, so m∠T cannot be zero or negative, and thus m∠T > 0.

Add m∠S to both sides.

m∠S + (m∠T) > m∠S + (0)

m∠S + m∠T > m∠S

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠S.

So, option 5 must be true.

Option 6. m∠S > m∠T

Not necessarily. While m∠S could be greater than m∠T, it doesn't have to be. (See examples 1 and 2 from option 3.)

So, option 6 does NOT have to be true.

4 0

2 years ago