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Nonamiya [84]
3 years ago
6

Substance X has a fixed volume, and the attraction between its particles is strong. Substance Y has widely spread out particles

and can be compressed. What can most likely be concluded about these substances?
Substance X is a crystal, and substance Y is a liquid.
Substance X is a gas, and substance Y is a plasma.
Substance X is a plasma, and substance Y is a crystal.
Substance X is a solid, and substance Y is a plasma.
Chemistry
2 answers:
ycow [4]3 years ago
6 0

Answer: Option (d) is the correct answer.

Explanation:

In solids, molecules are held together by strong intermolecular forces of attraction. As a result, they are unable to move from their initial position and can only vibrate at their mean position.

Hence, a solid has definite shape and volume. Solids cannot be compressed.

Whereas in plasma, molecules are hot ionized which include positively charged ions and negatively charged electrons. They collide much more rapidly with each other and are widely spreaded out.

Therefore, they occupy the volume of container in which they are placed. Plasma can be compressed.

Thus, we can conclude that substance X is a solid and substance Y is a plasma.

Bingel [31]3 years ago
3 0

Answer:

D) Substance X is a solid, and substance Y is a plasma.

Explanation:

Please give brainliest

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KIM [24]

Answer:

Li + ZnCO3

Explanation:

Li is higher than Zn on the activity series so Ln is more easily oxidized and prefers to be in a compound. For the rest of the reactions, the element that is higher on the activity series is already in the compound, so the reactions wouldn't happen.

3 0
3 years ago
Read 2 more answers
A compound is 21.6% Mg, 21.4% C, and 57.0% O. What is the empirical formula of the compound? ​
nignag [31]

Answer:

Compound x = MgC_{2}O_{4}

Explanation:

Let the compound be x

Assuming we have a 100g of compound x

<u>Given the following data;</u>

Magnesium, Mg = 21.6% = 21.6g

Carbon, C = 21.4% = 21.4g

Oxygen, O = 57.0% = 57.0g

Now, we would find the amount of moles for each element.

Atomic mass of Mg = 24.30g

Atomic mass of C = 12.01g

Atomic mass of O = 16.00g

<u>Amount of moles for Mg;</u>

21.6*(1/24.30) = 0.89mol

<u>Amount of moles for C;</u>

21.4*(1/12.01) = 1.78mol

<u>Amount of moles for O;</u>

57.0*(1/16.00) = 3.56mol

We then divide by the smallest to find the ratio;

0.89/0.89 = 1 Mol of Mg

1.78/0.89 = 2 Mol of C

3.56/0.89 = 4 Mol of O

Therefore, the ratio of Mg, C and O is 1:2:4.

Compound x = MgC_{2}O_{4}

Hence, the empirical formula of the compound is MgC_{2}O_{4}

7 0
3 years ago
A chemist has a 12.5 liter sample of neon gas at 1.00 atm and 30 c. If the chemist compresses the sample to 10.5 liters and hold
ycow [4]

Answer:

254.5 K

Explanation:

Data Given

initial volume V1 of neon gas = 12.5 L

final Volume V2 of neon gas = 10.5 L

initial Temperature T1 of neon gas = 30 °C

convert Temperature to Kelvin

T1 = °C +273

T1 = 30°C + 273 = 303 K

final Temperature T2 of neon gas = ?

Solution:

This problem will be solved by using Charles' law equation at constant pressure.

The formula used

                        V1 / T1 = V2 / T2

As we have to find out Temperature, so rearrange the above equation

                       T2 = V2 x T1 / V1

Put value from the data given

T2 = 10.5 L x 303 K / 12.5 L

T2 = 254.5K

So the final Temperature of neon gas = 254.5 K

8 0
3 years ago
Help me please with this question
Margarita [4]

Answer:

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Explanation:

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What organism is responsible for the cycling of nitrogen?
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4 0
3 years ago
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