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VikaD [51]
3 years ago
15

What visible evidence indicates that a solution is saturated?

Chemistry
2 answers:
rodikova [14]3 years ago
7 0
If clusters of the solute is still visible after the solution is stirred completely, this is evidence towards 'Over-Saturation'. <span />
AVprozaik [17]3 years ago
5 0
The greatest visual evidence you can use when trying to determine if a solution is saturated is to look and see if everything in the test tube is a single color and a single consistency.
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True or False When the attraction between the particles overcomes their motion the particles clump together to boil. ​
bixtya [17]

Answer:

False

Explanation:

It is wrong to claim that when the attraction between particles overcomes their motion, the particles will clump together to boil.

During boiling particles do no clump together, they tend to move apart more rapidly.

  • Boiling occurs when the vapor pressure overcomes the ambient atmospheric pressure.
  • The hotter part of the boiler close the heat source moves rapidly away because they have become less dense.
  • The colder and denser part sinks and this interaction sets up a convection cell.
6 0
3 years ago
Please help me I need help with this questions I’m very confused fused as to what the answer is please
zepelin [54]
Answer: This was because the experiment showed that a substance could emit radiation even while it was not exposed to light.
3 0
3 years ago
What is the molarity of a solution prepared from 85. 0 g cacl2 in 300. 0 g of solution? the density of the solution is 1. 05 g/m
Yuki888 [10]

Answer: 2.6 M

Explanation:

8 0
3 years ago
A piece of copper alloy with a mass of 85.0 g is heated from 30. °C to 45 °C. In the process, it absorbs 523 J of energy as heat
Ne4ueva [31]

Answer:

410.196 J/[kg*°C].

Explanation:

1) the equation of the energy is: E=c*m*(t₂-t₁), where E - energy (523 J), c - unknown specific heat of copper, m - mass of this copper [kg], t₂ - the final temperature, t₁ - initial temerature;

2) the specific heat of copper is:

c=\frac{E}{m*(t_2-t_1)}; \ => \ c=\frac{523}{0.085*(45-30)}=\frac{523}{1.275}=410.196[\frac{J}{kg*C}].

6 0
3 years ago
Check all that apply to sugar.
harina [27]

Answer:

Candy

Explanation:

its sweet and has a lot of sugar and acid

3 0
3 years ago
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