Number 3 please. I have no hope

There are some exceptions to the trends of first and successive ionization energies. For each of the following pairs, explain wh

NNADVOKAT [17]

Answer:

(b) IE₂ of Ga > IE₂ of Ge

Explanation:

Electronic configuration of Ga is [Ar] 3d¹⁰4s²4p¹

Electronic configuration of Ge is [Ar] 3d¹⁰4s²4p²

After 1st ionisation , Ga becomes [Ar] 3d¹⁰4s² and becomes stable . Its

2 nd ionisation requires higher amount of ionisation energy. In case of Ge , there are 2 electrons in outermost orbital so it becomes stable after ionisation of 2 electrons.

4 0

3 years ago

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The chemical equation below shows the reaction of glucose and oxygen.

goldfiish [28.3K]

• Aerobic respiration, photosynthesis

It is aerobic because it requires oxygen to be carried out. Anaerobic on the other hand does not require oxygen.

It’s two products would be the reactants for photosynthesis because in photosynthesis the reverse reaction takes place as glucose is produced along with water from carbon dioxide (CO2) and water (H2O) in the presence of chlorophyll and sunlight.

7 0

3 years ago

Which statement is correct about the location of electrons in an atom according to the Quantum mechanical model? A) Electrons ar

katrin2010 [14]

Answer:

B) Electrons are located in the cloud-like areas around the nucleus.

Explanation:

The quantum mechanical model of the atom does not consider the path through which an electron travels. It rather estimates the probability of where electrons can be found at each energy level.

The region of maximum probability of where an electron is located is sometimes called an electron cloud or orbital. Each orbital of an atom and the electrons accomodated are described completely by a set of four quantum numbers.

4 0

3 years ago

Complete the dissociation reaction and the corresponding Ka equilibrium expression for each of the following acids in water. (Ty

anastassius [24]

Answer :

(A) The dissociation reaction of $HC_2H_3O_2$ will be:

$HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

(B) The dissociation reaction of $Co(H_2O)_6^{3+}$ will be:

$Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}$

(C) The dissociation reaction of $CH_3NH_3^+$ will be:

$CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

(A) The dissociation reaction of $HC_2H_3O_2$ will be:

$HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)$

The equilibrium expression of $HC_2H_3O_2$ will be:

$K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

(B) The dissociation reaction of $Co(H_2O)_6^{3+}$ will be:

$Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)$

The equilibrium expression of $Co(H_2O)_6^{3+}$ will be:

$K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}$

(C) The dissociation reaction of $CH_3NH_3^+$ will be:

$CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)$

The equilibrium expression of $CH_3NH_3^+$ will be:

$K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}$

3 0

3 years ago

What is the molarity of a stock solution made from 40 grams of LiOH in 16050mL of water

tekilochka [14]

Answer: heck the chemistry app itll help you i dont know this answer but the app will tell u!

6 0

3 years ago