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3 years ago

Answer the 5 questions Listed below Please Show your Work

1 answer:

5 0

(6 1/3) / (5/6) = (19/3) / (5/6) = 19/3 * 6/5 = 114/15 = 38/5

3 - 7^2 + 3 * 4^2
3 - 49 + 3 * 16
3 - 49 + 48
- 46 + 48
2

(7b - 2) / (-a + 1)....a = -2, b = 3, c = -1/3
where is he c in this equation ? Because if I just use a and b, my answer is not an answer choice

(7b - 10) / (a - 1)...a = -1, b = 5, c = -2/3
same as before...where is the c in this equation

V = (pi) r^2* h
V = (pi)(5^2)(7)
V = (pi)(25)(7)
V = 175(pi)

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a cardboard box holds 31.25 cubic inches of creamy butter. The butter is molded into a square prism that is 5 inches long. How m

lesya [120]

Answer:

$62.5 \:in^2$

Step-by-step explanation:

Volume of the butter in the cardboard = 31.25 cubic inches

Length of the Molded Square Prism =5 Inches

Let the length of the square cross sectional area = x

Volume of the Prism $=x^2l$

Since l=5 Inches

$5x^2=31.25\\x^2=6.25\\x=2.5\: Inches$

Next, we determine the surface area of the New Cardboard box to be made.

Length of the Cardboard Box=5 Inches

Length of the square cross sectional area = 2.5 Inches

Total Surface Area $=2(x^2+xl+xl)=2(x^2+2xl)$

$=2(2.5^2+2(2.5)(5))\\=2(6.25+25)\\=2*31.25\\=62.5 \:in^2$

Therefore, $62.5 \:in^2$ of cardboard is needed,

4 0

3 years ago

Help please with this math ;-; I beg of you

RSB [31]

Answer:

49 - 9π

Step-by-step explanation:

Area of white portion = area of triangle - area of circle

To find the area of the triangle:

The area of a triangle can be calculated using this formula

$A=\frac{bh}{2}$ where b = base length and h = height

The height given is 7m and the base length given is 14m

That being said we plug in the given values into the formula

$\frac{14*7}{2} \\14*7=98\\\frac{98}{2} =49$

Hence, the area of the triangle is 49 sq meters.

To find the area of circle

( note that the area is in terms of pi; shown by the answer choices. )

Formula for area of a circle = $A=\pi r^2$

We are given the diameter ( 6m )

However, we need the radius

To convert diameter to radius we divide by 2

6/2 = 3 so the radius = 3m

Now we plug in 3 into the formula

$A=\pi 3^2\\3^2=9\\A=9\pi$

Remember we do not apply pi because the answer should be in terms of pi.

Now we subtract the two

Area of white portion = 49 - 9π

Hence, the answer is A

7 0

3 years ago

Read 2 more answers

When working problems on the calculator for trig functions, what are you supposed to have your calculator set to?

9966 [12]

Answer:

Degrees

Step-by-step explanation:

dont need one

4 0

4 years ago

It is an odd number. it is greater than 142. it is less than 156. rounded to the nearest ten, the rounded value is less than the

GaryK [48]

The odd numbers between 142 and 156 are these:

143, 145, 147, 149, 151, 153, and 155.

Of these, 143 to the nearest ten is 140.

Likewise, 151 to the nearest ten is 150.

And, 153 to the nearest ten is 150.

Of the seven original numbers, 143, 151, and 153 round to a nearest ten that
is less than the possible mystery number.

To the nearest hundred, 143 goes to 100; 151 goes to 200, and 153 goes to 200.

Of those three, only two round to a nearest hundred that is bigger than the mystery number.

Answer: 151 and 153 are the mystery numbers.

5 0

3 years ago

A shipping company is creating their own shipping boxes. They have created a box with a volume of 800in^3 , a height of 8 inches

Firdavs [7]

Answer:

Length = 10 inches

Width = 10 inches

Step-by-step explanation:

The perimeter of the base is 40 inches, so we can write the following equation:

2*Length + 2*Width = 40

Length + Width = 20 (eq1)

The volume of the box is 800 in3, so we have:

800 = Length*Width*8

Length*Width = 100 (eq2)

From the (eq1), we have:

Length = 20 - Width

Using this value of Length in (eq2), we have:

(20 - Width)*Width = 100

20*Width - Width^2 - 100 = 0

Using Bhaskara's formula, we have:

Delta = b^2 - 4ac = 400 - 400 = 0

Width = -b/2a = -20/(-2) = 10 inches

Length = 20 - Width = 20 - 10 = 10 inches

So the length is 10 inches and the width is 10 inches

3 0

3 years ago

Read 2 more answers