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3 years ago

Who ever answers this will get a cookie from batman

Mathematics

1 answer:

Otrada [13]3 years ago

5 0

Answer:

(0,-2)

(1,-1)

(5,-3)

Step-by-step explanation:

To solve this question, all you need to do is put the x coordinate in for x and the y coordinate for y. (x,y) We need to find the equation that is less than or equal to 3.

You might be interested in

Find an equation of variation where y varies directly as x and y = 7 when x = 0.5 .

Alisiya [41]

Answer:

y = 14x

Step-by-step explanation:

Use the direct variation equation, y = kx

Plug in 7 as y and 0.5 as x, and solve for k:

y = kx

7 = k(0.5)

14 = k

Plug this into the equation:

y = kx

y = 14x

So, the equation of variation is y = 14x

4 0

3 years ago

indictate which of the following are propositions.For the ones which are propositions, determine the truth value.(a) The integer

Semmy [17]

Answer:

Step-by-step explanation:

When we propose an hypothesis, it is either true or false. The same goes for a proposition.

The required objective here is to determine the truth value in the following proposition.

(a) The integer 24 is prime.

(b) Is the integer 315 even?

(d) -4 ∈ Ζ

From the first option:

(a) The integer 24 is prime.

The sentence is a proposition but the truth value is FALSE because a prime number is a number that can only be divide by 1 and itself but in the case of 24, Its factors include 1,2,3,4,6,8,12 and 24 which make 24 to falsify the proposition of being a prime number.

(b) Is the integer 315 even?

This option is not a proposition but rather a question since it has a question mark, however, 315 is an odd number since it is not divisible by 2.

( c) The sum of 3 and 4 is 12.

This is a proposition and the truth value is FALSE

The sum of 3+4 = 7 ; Hence; 7 ≠ 12

(d) -4 ∈ Ζ

This is a proposition and the truth value is TRUE.

-4 ∈ Ζ is read as ( minus four is an integer (∈) of Z )

Yes, this is a proposition and its Truth value is TRUE , since minus four is an integer (∈) of Z

6 0

3 years ago

A day care program has an average daily expense of $75.00. The standard deviation is $5.00. The owner takes a sample of 64 bills

SpyIntel [72]

I think the answer is 61 dont quote me on it im awful at math

6 0

3 years ago

DATE:

Cloud [144]

Answer: See explanation

Step-by-step explanation:

Your question isn't well written but let me help out. I saw a similar question.

Example 1: Aling Luz bought 3/8 yards of linen cloth which cost Php 72.00 per yard. She gave Php 1000.00 to the cashier.How much change will she get?

Since we are informed that Aling Luz bought 3/8 yards of linen cloth which cost Php 72.00 per yard, the amount she'll pay will be:

= 3/8 × 72

= Php 27

Since she gave the cashier Php 1000, her change will be:

= 1000 - 27

= Php 973

6 0

4 years ago

Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.

sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
The diagonals are perpendicular

Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

$|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}$

$\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}$

$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

$\implies m_{EG}=\frac{2c}{0}$

The slope of EG is undefined hence it is a vertical line.

The slope of DF is $m_{DF}=\frac{c-c}{a+b-(-a-b)}$

$\implies m_{DF}=\frac{0}{2a+2b)}=0$

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

$m_{DE}=\frac{c}{a+b)}$

The slope of FG is $m_{FG}=\frac{c-0}{a+b-0}$

$\implies m_{FG}=\frac{c}{a+b}$

5 0

3 years ago