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3 years ago

The graphs of two functions are shown.

Mathematics

2 answers:

Naily [24]3 years ago

3 0

Range, Maximum, and y-intercept

Otrada [13]3 years ago

3 0

Y-intercept is definitely one

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Pedro le dice a María si cambias los billetes de 10 € que tienes por billetes de 5 € y los billetes de 5 € por billetes de 10 €

Bad White [126]

Answer: Maria has 10 bills of 5€ and 10 bills of 10€.

She has a total of 150€.

Step-by-step explanation:

Let be "f" the number of 5€ bills that Maria has and "t" the number of 10€ bills that Maria has.

Set up a system of equations:

$\left \{ {{f+t=20} \atop {5f+10t=10f+5t}} \right.$

Use the Substitution method to solve the system of equations:

1. Solve for "f" from the first equation:

$f=20-t$

2. Substitute the equation obtained into the second equation and solve for "t".

Then:

$5(20-t)+10t=10(20-t)+5t\\\\100-5t+10t=200-10t+5t\\\\20t-10t=100\\\\t=\frac{100}{10}\\\\t=10$

3. Substitute the value of "t" into the equation $f=20-t$ and evaluate:

$f=20-10\\\\f=10$

Therefore, Maria has 10 bills of 5€ and 10 bills of 10 €.

So the total amount of money she has, is:

$Total=10(5)+10(10)=150$

She has a total of 150€.

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3 years ago

If you are selling bag of candy would you want ti sell the candy in ounces or pounds? Explain.

7nadin3 [17]

You would want to sell the bag of candy in ounces, unless you have way too much candy.

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3 years ago

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30 girls and boys have planned for a picnic. There is a ratio of 3 girls to 7 boys. How many boys are there?

nirvana33 [79]

Should be 21 boys because 7+7+7 equal 21 and 3+3+3 equal 9 which equals 30

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2 years ago

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Help me please!!!! i dont now the answer

Marat540 [252]

-1/10 is your answer .

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2 years ago

George’s parents are saving for his college fund. they put $5,000 into an interest bearing account with a compound interest rate

sergey [27]

so hmmm is compound interest, now, we'll be assuming the compounding period is per year, or annually, so it happens once per year.

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &15 \end{cases} \\\\\\ A=5000\left(1+\frac{0.055}{1}\right)^{1\cdot 15}\implies A=5000(1.055)^{15}$

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2 years ago