Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
It is helpful to estimate quotients when the number is very big.
Answer:
B is the area of the base
Step-by-step explanation:
V= 1/3 Bh
V is the volume
B is the area of the base
h is the height of the pyramid
0.48p
Step-by-step explanation:
1.20÷10=0.12
0.12×4=0.48
Answer:
{x | x ≤ -20}
Step-by-step explanation:
x + 17 ≤ -3
Subtract 17 from each side
x + 17-17 ≤ -3-17
x ≤ -20
