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mario62 [17]
3 years ago
8

The hypotenuse of a right triangle is 26 millimeters. One leg of the right triangle is 10 millimeters. What is the length of the

other leg?
Mathematics
1 answer:
Daniel [21]3 years ago
3 0
<span>Hypotenuse = 26 mm </span>

1st Leg        = 10 mm

Other Leg = x.

By Pythagoras Theorem:

x² + 10² = 26²

<span>x² + 100 = 676 </span>

x² = 676 - 100

x² = 576

x = √576

x = 24

<span>The other leg is 24 mm</span>
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<em><u>Solution:</u></em>

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

<em><u>The volume of container is given as:</u></em>

v = length \times width \times height

Given that volume of the container is 216 cubic feet

216 = l \times w \times h

Substitute eqn 1 and eqn 2 in above formula

216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0

Solve by factoring

(h-8)(h^2+4h+27) = 0

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

h - 8 = 0\\\\h = 8

Also,

h^2+4h+27 = 0

Solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

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h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

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h = 8

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"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

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3 years ago
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