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lukranit [14]
3 years ago
9

Kali is very organized, very creative, and likes to come up with different slogans for commercials. Which career pathway would b

est utilize Kali’s skills? Management Administration Marketing Human Resources
Mathematics
2 answers:
BabaBlast [244]3 years ago
5 0
Marketing would be best since you’d have to create a product and make a logo and tagline for it as well. So creativity is definitely a good trait for a marketer.
nika2105 [10]3 years ago
5 0

Answer:

marketing

Step-by-step explanation:

i took the test on edge. and got it right

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Suppose you have 48 feet of fencing to enclose a rectangular dog pen. The function A=24x-x^2, where x = width, gives you the are
Alecsey [184]

Answer:

Width: 12 ft

Maximum area: 144 ft²

Step-by-step explanation:

A = 24x – x²

A = –x² + 24x

A = –(x² – 24x)

A = –(x² – 24x + 144) + 144

A = –(x – 12)² + 144

Therefore, the maximum area of 144 ft² occurs at x = 12 ft.

3 0
3 years ago
Which one is the answer???
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D is correct because y on I doesn't equal y on II.
5 0
3 years ago
Let v = 3i + 2j and w = 2i + 3j. Sketch v, w, v + w, 2w, and v − w in the plane
Nimfa-mama [501]

Answer:

Step-by-step explanation:

In the argand plane for plotting points of complex numbers we take i coefficient as x and j coefficient as y and plot as we plot regular points on the graph.

v=3i+2j

Point is (3,2) A

w =2i+3j , Point is (2,3) B

v+w = 5i +5j Point is (5,5) C

2w = 4i+6j , point is (4,6)

v-w = i-j Point (1,-1)

Please find enclosed the above points plotted on the graph.

5 0
3 years ago
Which of these is equal to 35 (8 – 3)? A. (35 + 8) – (35 + 3) B. (35 × 8 ) + (35 × 3) C. (35 × 8) – (35 × 3) D. (35 × 11)
liq [111]
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6 0
3 years ago
A trough has ends shaped like isosceles triangles, with width 5 m and height 7 m, and the trough is 12 m long. Water is being pu
Svet_ta [14]

Answer:

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

Step-by-step explanation:

First we need to find the volume of the trough given its dimensions and shape: (it has a prism shape so we can directly use that formula OR we can multiply the area of its triangular face with the length of the trough)

V = \dfrac{1}{2}(bh)\times L

here L is a constant since that won't change as the water is being filled in the trough, however 'b' and 'h' will be changing. The equation has two independent variables and we need to convert this equation so it is only dependent on 'h' (the height of the water).

As its an isosceles triangle we can find a relationship between b and h. the ratio between the b and h will be always be the same:

\dfrac{b}{h} = \dfrac{5}{7}

b=\dfrac{5}{7}h this can be substituted back in the volume equation

V = \dfrac{5}{14}h^2L

the rate of the water flowing in is:

\dfrac{dV}{dt} = 6

The question is asking for the rate of change of height (m/min) hence that can be denoted as: \frac{dh}{dt}

Using the chainrule:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

the only thing missing in this equation is dh/dV which can be easily obtained by differentiating the volume equation with respect to h

V = \dfrac{5}{14}h^2L

\dfrac{dV}{dh} = \dfrac{5}{7}hL

reciprocating

\dfrac{dh}{dV} = \dfrac{7}{5hL}

plugging everything in the chain rule equation:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

\dfrac{dh}{dt}=\dfrac{7}{5hL}\times 6

\dfrac{dh}{dt}=\dfrac{42}{5hL}

L = 12, and h = 1 (when the water is 1m deep)

\dfrac{dh}{dt}=\dfrac{42}{5(1)(12)}

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

6 0
4 years ago
Read 2 more answers
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