A Web interface which presents integrated personalized business content delivered to senior managers is an XML document.
<h3>What is an
XML document?</h3>
XML documents can be seen to be a text files which is a phrase "XML document" that is used in describing the file or data stream having some form of structured data.
This could be e-commerce transactions as well as server APIs, hence Web interface which presents integrated personalized business content delivered to senior managers is an XML document.
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Answer:
C) Return on equity will increase dramatically
Explanation:
Return on equity (ROE) is a profitability ratio and it is calculated using the following formula:
ROE = net income/ shareholders' equity
If shareholders' equity is reduced by 50%, and the net income remains stable, then ROE should double.
For example, net profit = $100, shareholders' equity = $1,000
ROE = $100 / $1,000 = 0.10
If shareholders' equity is reduced by 50%, then the new ROE will be:
ROE = $100 / $500 = 0.20
Answer:
resource smoothing
Explanation:
According to the definition provided in the question we can say that this is regarding resource smoothing. Like mentioned in the question this term refers to a management technique that adjusts the resources so that the requirements do not surpass the resource limits that the company has specified, by delaying the noncritical activities in order to allow for the important ones first.
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Buy the car if it is good quality... or if he has enough money
Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80
