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2 years ago

(1 pt) Which answer best describes the solution to the equation 3m – 9 = 9 + 3m?

1 answer:

3 0

3m-9=9+3m
add 9 to both sides
3m=18+3m
minus 3m both sides
0=18
false
no solution

the best discription would be an empty solution set

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Write a quadratic function whose zeros are -12 and -2.

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Answer:

(x+12) (x+2)

x(x+12)+2(x+12)

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x^2+14x+24

Step-by-step explanation:

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Step-by-step explanation:

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Which expression is equivalent to the given expression?

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The answer is 4a - 12 so b.

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Kasey asked 6 of her friends how many episodes of their favorite show they

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Answer:

Step-by-step explanation:

6 friends

Mean - 10

Median - 9.5

Range - 14

3 friends watched 12, 13, and 18 movies.

Let's find the sum, this will help us find the total number of movies the other 3 friends watched.

12 + 13 + 18 = 43

The mean is all their movies added toether, divided by the number of friends.

m = number of movies the other friends watched.

(43 + m) / 6 = 10 Multiply each side by 6

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A. 4+6+7 = 17

B. 4+4+7 = 15

C. 5+8+9 = 22

D. 2+3+5 = 10

We know the answer is A.

We can check it by looking at the Median, the median is the middle number, if there are an even number of samples, you add the 2 middle numbers together and divide by 2.

4, 6, 7, 12, 13, 18

So 7+12 = 19

19/2 = 9.5

So we know for sure A is correct!

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3 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

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3 years ago