You can use this formula: <span>vf^2=0+2(9.8)(M)
solve it out like so:
vf^2=0+2(9.8)(180)
vf^2=2(1764)
vf^2=3528
now, square both sides to cancel out the power of 2. you are left with:
about 59.4 m/s</span>
1.)
Velocity is in m/s, and acceleration is in m/s^2 like you said. Because of this, we can calculate this by dividing the speed by the time it took to get to that speed.
(20 meters/second) / 10 seconds = 2 meters/ second^2
2.)
Same thing with the first one.
(100 meters/second) / 4 seconds = 25 meters / seconds^2
Eight units I'm pretty sure
Yes they are equal they both have a side that is 25 degrees
Answer:
125 meters
Step-by-step explanation:
Let distance = d and time is t
Using the variation;
d = k t^2
So let’s us get k
80 = k * 4*2
16k = 80
k = 80/16 = 5
So for 5 seconds, the distance would be;
d = 5 * 5^2
d = 125 meters
