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3 years ago

What is the perimeter, P, of a rectangle that has a length of x + 6 and a width of y - 1?

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

5 0

Answer: P = 2x + 2y + 10

Step-by-step explanation: The perimeter (P) of a rectangle is given as

P = 2L + 2W

By factorizing the right hand side of the equation we now have

P = 2(L + W)

However, the length of the rectangle is given as x + 6 and the width is given as y - 1

If P = 2(L + W), then

P = 2(x + 6 + {y - 1} )

P = 2(x + 6 + y -1)

P = 2(x + y + 5)

After expanding the bracket, we now have

P = 2x + 2y + 10

Gnom [1K]3 years ago

3 0

Answer:

just took the test the answer is P = 2x + 2y + 10

Step-by-step explanation:

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3 years ago

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2 years ago

M is the midpoint of the segment. Find the length of XM.

Lelechka [254]

Answer:

x=2 and XM=11

Step-by-step explanation:

because M is the midpoint of the line, you know that both XM and ZM are equal and you know an expression for the lengths of both of these.

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4x+3=3x+5 so by subtracting the 3x from the right side, moving it over to the left and subtracting 3 from the left side to move it over to the right, you get:

x=2

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2 years ago

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evablogger [386]

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