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Dmitriy789 [7]
3 years ago
14

A coin is tossed 20 times. It lands on heads 9 times. What is the P(H) according to your experiment? Write your answer as a frac

tion, decimal, and percent.
Mathematics
1 answer:
Mama L [17]3 years ago
8 0

Answer:

\frac{9}{20}=0.45=45%

Step-by-step explanation:

Probability is found by first forming a fraction where the numerator represents the number of desired outcomes and the denominator represents the total number of outcomes.  In this case, the desired outcomes is the amount of times the coin lands on heads (9) and the total outcomes is the number of times the coin is tossed (20):

\frac{9}{20}

Divide numerator by denominator to get a decimal: 9÷20= 0.45

Multiply the decimal by 100 to get a percent: 0.45 x 100 = 45%

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3 years ago
If the simple interest on 3,000​$ for 3 years is ​450$​, then what is the interest​ rate?
Artyom0805 [142]

Answer/Step-by-step explanation:

The interest rate is 15% for every 3 years. To find the interest rate subtract the money from the total. Then, divide the total from the difference. Now subtract the quotient from 100 and multiply it by 100 to fin the percentage.

3000 - 450 = 2550

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1) 49 - 3% =<br> what is the answer to THIS question
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Solve the given initial-value problem. (Use x as the independent variable.) 2y'y'' = 1, y(0) = 2, y'(0) = 1
elixir [45]

Answer: y(x) = (2/3)*(x + 1)^(3/2) + 1/3.

Step-by-step explanation:

We have the differential equation:

2*y'(x)*y''(x) = 1.

y(0) = 2

y'(0) = 1.

I will use the change:

u = y'

u'= y''

Then we must solve:

2*u*u' = 1.

The product does not depend on x:

u*u' = 1/2.

By looking at the problem, i know that the functions must be something like:

u = a*(x + b)^n

Where a and b are real numbers.

u' = n*a*(x + b)^(n - 1)

such that:

(x + b)^n*(x + b)^(n - 1) does not depend on x

This means that:

(x + b)^n*(x + b)^(n - 1)  = (x + b)^(n + n - 1) = 0

n + n - 1 = 0

2n = 1

n = 1/2

Then:

u = a*(x + b)^(1/2)

u' = (a/2)*(x + b)^(-1/2)

The differential equation becomes:

u*u' = 1/2

a*(x + b)^(1/2)* (a/2)*(x + b)^(-1/2) = 1/2

(1/2)*a^2 = 1/2

a^2 = 1.

And by the initial conditions, we have:

y'(0) = u(0) = 1

then:

u(0) = a*(0 + b)^(1/2) = a*b^(1/2) = 1

now, if a = -1, then b^(1/2) must be negative, this can not really be then we must have:

a = 1

u(0) = 1*b^(1/2) = 1

then b = 1.

u(x) = (x + 1)^(1/2).

And remember that y'(x) = u(x).

Then we need to integrate u(x) over x.

let's use the change of variables:

w = x +  1

dw = dx

Then the integration of u(x) is:

y(w) = ∫(w)^(1/2)dw = (2/3)*w^(3/2) + c

where c is a constant of integration.

now we can go back to x:

y(x) = (2/3)*(x + 1)^(3/2) + c

And we know that:

y(0) = 1 = (2/3)*(0 + 1)^(3/2) + c

         1 = (2/3)*1 + c

1 - 2/3 = c

     1/3 = c

Then:

y(x) = (2/3)*(x + 1)^(3/2) + 1/3.

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3 years ago
In a computer simulation, a satellite orbits around Earth at a distance from the Earth's surface of miles. The orbit is circular
Sloan [31]
Hi, thank you for posting your question here at Brainly.

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8 0
3 years ago
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