$6.
You can get this by dividing the original number by 3 and then the new answer by 2.
Answer:
No, Matt did not solve the equation correctly
Correct Answer: x = 8
Step-by-step explanation:
4(x + 2) = 30
Step 1: Distribute
4x + 2 = 30
This is his mistake, he should completely distribute 4
to x and 2
Step 2: Subtract 2 from both sides/Isolate x
4x = 28
This part is done correctly, but wrong because of Step 1
Step 3: Divide both sides by 4
x = 7
This is correct, but again, he messed up on Step 1
<h3>
Let's find the correct answer to this equation:</h3><h3>4(x +2) = 30</h3>
Step 1: Distribute
Remember to distribute 4 to all terms in the parenthesis.
4(x + 2) = 4(x) + 4(2)
= 4x + 8
4x + 8 = 30
Step 2: Subtract 8 from both sides/Isolate x
Move all the terms that do not belong to x to the other side. We can do this by subtracting 8 from both sides
(opposite operation of adding 8)
4x + 8 = 30
4x = 30 - 8
4x = 32
Step 3: Divide both sides by 4/Isolate x
Now we want x by itself. Since x is being multiplied by 4, we have to use the opposite operation, dividing by 4, to have x on one side by itself
4x = 32
4(x) = 32
x = 32 ÷ 4
x = 8
-Chetan K
We want to find the value that makes

To find it we must look at the standard normal table, using the complementary cumulative table we find that

Then, using the z-score we can find the minimum score needed, remember that

Where
σ = standard deviation
μ = mean
And in our example, x = minimum score needed, therefore

Rounding to the nearest integer the minimum score needed is 568, if you get 568 you are at the top 20.1%.
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Answer:
Step-by-step explanation:
1 m = 39.3701 in 1m = 3.28084 ft
4 m = 157.48 in 4m = 13.1234 ft