In 1957, Katherine provided some of the math for the 1958 document notes on space technology. She made contributions to the United States aeronautics and space programs with NASA
Answer:
(-∞ , -6] ∪ [6 , +∞)
Step-by-step explanation:
<u>Let D be the domain of f </u>.
D = {x ∈ IR ; where x² - 36 ≥ 0}
x² - 36 ≥ 0
⇔ x² ≥ 36
⇔ x² ≥ 6²
⇔ √(x²) ≥ √(6²)
⇔ |x| ≥ 6
⇔ x ∈ (-∞ , -6] ∪ [6 , +∞)
Answer:
- 0.6
Step-by-step explanation:
Start point: (5,6)
End point: (-5,12)
rate of change = (12-6) / (-5-5) = 6/-10 = - 3/5 = - 0.6
Answer:
rc length = 10 * 8pi/5
= 16pi
This is the circumference of the base
(a) 2pir = 16pi where r = radius of base
2r = 16
r = 8 cm
(b) 10^2 = h^2 + 8^2
h^2 = 100 - 64
= 36
h = 6 cm
To solve for the A or the principal amount plus interest you can use two formulas:
A = P + I
Where: P = Principal
I = Interest
or you can use
A = P (1+ rt)
Where: P = principal
r = rate in decimal
t = time in years
With your given you can use the second one, without having to use the first.
Given that the Principal amount is $222 and the rate is 12% and time is 10 years, we first need to convert your rate into decimal by dividing the value in percent by 100 which will yield 0.12.
Then now we can just input the data that you know into the formula:
A = P(1+ rt)
= $222(1 + (0.12)(10))
= $222(2.2)
= $488.40
Your A is then equal to $488.40
If you need to get the simple interest all you need to use is the first formula given:
A = P + I
for the interest you transpose the P to the side of the A and you will get:
I = A - P
= $488.40 - $222
= $266.40
$266.40 is the added interest to the principal amount.
