Answer:
0.086J/g°C
Explanation:
The following data were obtained from the question:
Mass (M) = 30g
Initial temperature (T1) = 10°C
Final temperature (T2) = 45°C
Change in temperature (ΔT) = T2 – T1 = 45°C – 10°C = 35°C
Heat (Q) released = 90J
Specific heat capacity (C) of wood =..?
We can obtain the specific heat capacity of the wood as follow:
Q = MCΔT
90 = 30 x C x 35
Divide both side by 30 x 35
C = 90/(30 x 35)
C = 0.086J/g°C.
Therefore, the specific heat capacity of the wood is 0.086J/g°C.
Answer:
3S₈ + 28Br₂ => 8S₃Br₇
Explanation:
Start with either sulfur (S) or bromine (Br) and balance ...
3S₈ + Br₂ => 8S₃Br₇ or S₈ + 7/2Br₂ => S₃Br₇
Balance the remaining reactant ...
3S₈ + 56/2Br₂ => 8S₃Br₇
Remove fractions by multiplying by the fraction's denominator
2(3S₈ + 56/2Br₂ => 8S₃Br₇) => 6S₈ + 56Br₂ => 16S₃Br₇
Reduce to smallest whole number ratio => standard equation at STP ...
3S₈ + 28Br₂ => 8S₃Br₇
Explanation:
Let there be 1 mole of CoCl2.
Mass of CoCl2 = 1mol * (129.839g/mol) = 129.839g
Mass of H2O = 309.99g - 129.839g = 180.151g
Moles of H2O = 180.151g / (18g/mol) = 10mol
Hence the mole ratio of CoCl2 to H2O is 1 : 10.
