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beks73 [17]
3 years ago
9

which molecule can diffuse from the digestive tract into the human blodstream without first being digested

Chemistry
1 answer:
sweet [91]3 years ago
5 0
Water molecules. It doesn't has to be digested and can be directly absorbed into the small intestine and large intestine. water does not has a type of enzyme that digest it, unlike other nutrients compounds such as carbohydrates or protein.
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A sample of wood with a mass of 30 g has its
anzhelika [568]

Answer:

0.086J/g°C

Explanation:

The following data were obtained from the question:

Mass (M) = 30g

Initial temperature (T1) = 10°C

Final temperature (T2) = 45°C

Change in temperature (ΔT) = T2 – T1 = 45°C – 10°C = 35°C

Heat (Q) released = 90J

Specific heat capacity (C) of wood =..?

We can obtain the specific heat capacity of the wood as follow:

Q = MCΔT

90 = 30 x C x 35

Divide both side by 30 x 35

C = 90/(30 x 35)

C = 0.086J/g°C.

Therefore, the specific heat capacity of the wood is 0.086J/g°C.

5 0
3 years ago
Which of the following Gila Monster adaptations is based on the reproductive cycles of Gambel’s quails and cottontail rabbits?
Natasha_Volkova [10]

Answer:

B

Explanation:

3 0
3 years ago
What is the balance of S8+Br2=S3Br7
GalinKa [24]

Answer:

     3S₈  +  28Br₂ => 8S₃Br₇

Explanation:

Start with either sulfur (S) or bromine (Br) and balance ...

    3S₈  +  Br₂ => 8S₃Br₇    or      S₈  +  7/2Br₂ => S₃Br₇

Balance the remaining reactant ...

    3S₈  +  56/2Br₂ => 8S₃Br₇    

Remove fractions by multiplying by the fraction's denominator

    2(3S₈  +  56/2Br₂ => 8S₃Br₇)     =>     6S₈  +  56Br₂ => 16S₃Br₇      

Reduce to smallest whole number ratio => standard equation at STP ...

        3S₈  +  28Br₂ => 8S₃Br₇

8 0
3 years ago
Consider the type of plant in which edible spoons and other disposable spoons would be produced. What systems would have to be i
Amiraneli [1.4K]
The plants are on the edible spoons
4 0
3 years ago
A hydrated sample of cobalt II chloride has a molar mass of 309.99 g/mol. What is the mole ratio between cobalt II chloride and
VLD [36.1K]

Explanation:

Let there be 1 mole of CoCl2.

Mass of CoCl2 = 1mol * (129.839g/mol) = 129.839g

Mass of H2O = 309.99g - 129.839g = 180.151g

Moles of H2O = 180.151g / (18g/mol) = 10mol

Hence the mole ratio of CoCl2 to H2O is 1 : 10.

4 0
3 years ago
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