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2 years ago

How much energy is lost to condense 300. grams of steam at 100.C?

Chemistry

1 answer:

True [87]2 years ago

3 0

Energy lost to condense = 803.4 kJ

<h3>Further explanation</h3>

Condensation of steam through 2 stages:

1. phase change(steam to water)

2. cool down(100 to 0 C)

1. phase change(condensation)

Lv==latent heat of vaporization for water=2260 J/g

$\tt Q=300\times 2260=678000~J$

2. cool down

c=specific heat for water=4.18 J/g C

$\tt Q=300\times 4.18\times (100-0)=125400$

Total heat =

$\tt 678000+125400=803400~J$

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The key enzyme in the regulation of the citric acid cycle is:.

bixtya [17]

The key enzyme in the regulation of the citric acid cycle is citrate synthase. It functions in the mitochondria.

<h3>Citrate synthase and cellular respiration </h3>

Cellular respiration is a series of reactions that produce ATP by using the energy stores in the chemical bonds of foods.

Cellular respiration is divided into glycolysis, the citric-acid cycle and oxidative phosphorylation.

Citrate synthase is an enzyme found in the mitochondrial matrix, which is involved in the citric acid cycle.

Learn more about cellular respiration here:

brainly.com/question/2809259

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2 years ago

What is the velosity of a 72.3 kg jogger with a kinetic energy of 1080.0 J?

Svet_ta [14]

Answer: 5.47m/s

Explanation:

Mass = 72.3kg

K.E = 1080.0J

V =?

K.E = 1 /2MV^2

V^2 = 2K.E /M = (2x1080)/72.3

V = sqrt [(2x1080)/72.3]

V = 5.47m/s

7 0

3 years ago

A volume of 80.0 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. I

murzikaleks [220]

Answer:

The mass of the steel bar is 26.833 grams

Explanation:

<u>Step 1: </u>data given

ΣQ gained = ΣQ lost

Q=m*C*ΔT

with m = mass in grams

with C= specific heat capacity ( in J/(g°C))

with ΔT = change in temperature = T2-T1

Qsteel = Qwater

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

Mass of steel = TO BE DETERMINED

mass of water =⇒ since 1mL = 1g : 80 mL = 80g

Csteel =0.452 J/(g °C

Cwater = 4.18 J/(g °C

initial temperature steel T1 : 2 °C

final temperature steel T2 = 21.3 °C

initial temperature water T1 =22 °C

final temperature water T2 = 21.3 °C

<u>Step 2:</u> Calculate mass of steel

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

msteel * 0.452 *(21.3-2) = 80 * 4.18 * (21.3-22)

msteel = (80 * 4.18 * (-0.7)) / (0.452 * 19.3)

msteel = -234.08 / 8.7236

msteel = -26.833 g

Since mass can't be negative we should take the absolute value of it = 26.833g

The mass of the steel bar is 26.833 grams

6 0

3 years ago

Given the reaction:

WARRIOR [948]

Answer:

4 moles

Explanation:

From the equation 1 mole of C6H1206 produces 6 moles of CO2.

Therefore the answer is 24/6 = 4 moles of C6H1206.

6 0

2 years ago

If you burn 29.4 g of hydrogen and produce 263 g of water, how much oxygen reacted?

vovikov84 [41]

The reaction between hydrogen and oxygen to form water is given as:

$H_2 + O_2 \rightarrow H_2O$

The balanced reaction is:

$2H_2 + O_2 \rightarrow 2H_2O$

According to the balanced reaction,

4 g of hydrogen ( $4\times 1$ ) reacts with 32 g of oxygen ( $2\times 16$ ).

So, oxygen reacted with 29.4 g of hydrogen is:

$\frac{29.4\times 32}{4} = 235.2 g$

Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.

7 0

3 years ago