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AlekseyPX
4 years ago
10

A certain weak acid, HA, has a Ka value of 2.6×10−7. Calculate the percent ionization of HA in a 0.10 M solution.

Chemistry
1 answer:
Andrej [43]4 years ago
4 0

Answer:

The percent ionization is 0,16%

Explanation:

The percent ionization is defined as the number of ions that exist in a substance.

PI=\frac{[A-]}{[HA]} x100

First, we find the [A-] using the ka equation

HA ⇄ H^{+} + A^{-}

[H+] = [A-]

Ka=\frac{[H+][A-]}{[HA]}\\ \\

since the ionization constant is very small we can assume that the final concentration of [HA] is the same

Ka=\frac{[H+]^{2} }{[HA]} \\\\

[H+]=\sqrt[2]{Ka.[HA]} \\\\

[H+] =\sqrt{(2,610^{-7} )(0,1)}  = 1,61210^{-4}

Now we calculate the percent ionization using these values

PI=\frac{1,61210^{-4} }{0,1} X100

PI=0,16%

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