Answer:
Solving for 
we got 
and replacing this we got:
And then the best option for this case would be:
b.csc x
Step-by-step explanation:
For this case we have the following expression given:
We know from math properties that the definition for cot is
If we use this definition we got:
Now we can use the following identity:
Solving for we got and replacing this we got:
And then the best option for this case would be:
b.csc x
Answer:
<h2>W = 16</h2>
Step-by-step explanation:
<h3>
![\sqrt[4]{W} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7BW%7D%20%20%3D%202)
</h3>
To find W raise each of the sides of the equation to the power 4 to make W stand alone
That's
<h3>
![( { \sqrt[4]{W} })^{4} = {2}^{4}](https://tex.z-dn.net/?f=%28%20%7B%20%5Csqrt%5B4%5D%7BW%7D%20%7D%29%5E%7B4%7D%20%20%3D%20%20%7B2%7D%5E%7B4%7D%20)
</h3>
We have
W = 2⁴
We have the final answer as
<h3>W = 16</h3>
Hope this helps you
Answer:
Step-by-step explanation:
(x−a)(x−b)=x2−(a+b)x+ab
Now, this with the third bracket.
(x2−(a+b)x+ab)(x−c)=x3−(a+b+c)x2+(ac+bc+ab)x−abc
But there’s another way to do this, which is easier. Assume the given expression is equal to 0, then, we can form a cubic equation as
x3−(sum−of−roots)x2+(product−of−roots−taken−two−at−a−time)x−(product−of−roots) , which is essentially what we got above.
Answer:
To determine the nature of roots of quadratic equations (in the form ax^2 + bx +c=0) , we need to calculate the discriminant, which is b^2 - 4 a c. When discriminant is greater than zero, the roots are unequal and real. When discriminant is equal to zero, the roots are equal and real.
