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3 years ago

What is 1188.28856995 to the nearest ten

Mathematics

2 answers:

klemol [59]3 years ago

7 0

1188.3
So because the 8 is higher than 5, the 2 becomes a 3 and the rest become 0’s

OleMash [197]3 years ago

5 0

Answer:

1190

Step-by-step explanation:

1188 would be the nearest one but since we are doing the nearest ten which is the first eight it would be 1190 because the second 8 is over 5 and we round up.

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Your credit card company charges 18 % APR (Annual Percentage Rate )

hjlf

Answer:

Step-by-step explanation:

7 0

2 years ago

How can I use models to help me divide??

Ivan

You can use models to help you divide by making the number of models as your divisor. For example let's say I am dividing 8 ÷ 2. So you would make 8 circles (doesn't have to be circle it can be whatever like squares) and then make groups of 2 until you run out of circles. Then how many groups there are is your answer. 8÷2=4. Hope I helped!

4 0

2 years ago

8. A cellphone company charges $29.99 per month for the first 500 minutes of calls and $0.30 a minute for any calls over the 500

scZoUnD [109]

Answer:

C) $64.49

Step-by-step explanation:

let 'x' = #minutes

cost = 29.99 + 0.3(x-500)

= 29.99 + .3(115)

= 29.99 + 34.50

= $64.49

8 0

2 years ago

What is the mean of this data: 23, 37, 11, 58, 13, 45

nata0808 [166]

Step-by-step explanation:

Mean= Sumof all the numbers/ number of data

So,

23+37+11+58+13+45=187

Now...

187/6=31.166666667 Answer

hope it helps....

8 0

2 years ago

Read 2 more answers

The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using

Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

68.27% of the data lies within one standard deviation of the mean.

95.45% of the data lies within two standard deviations of the mean.

99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

$\Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})$

where the symbol $\Phi$ (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, $\mu$ is the mean and $\sigma$ is the standard deviation of the normal distribution defined as $N(\mu, \ \sigma)$ .

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution $N(113, \ 12)$ ,

$\Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973$

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

5 0

2 years ago