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3 years ago

X + y = 21 6x +4y=104

Mathematics

1 answer:

Bond [772]3 years ago

4 0

Answer:

look at the picture shown

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A person wishes to mix coffee worth $9 per lb with coffee worth $3 per lbto get 240 lbsof a mixture worth $5 per lbHow many po

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In order to get $5 per pound, you need a ratio of 1:2. One $9 for every two $3 will get you $5 per pound, since 9 + 3 + 3 is 15, divided by 3 pounds is $5. For 240 pounds, divide by three (since there is one $9 and two $3). This is 80 times the 3 pounds at $5.
Therefore, 1 × 80 is 80 pounds of $9 coffee, and 2 × 80 is 160 pounds if $3 coffee. which totals 240 pounds at $5 per pound.

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18. Chicken patties are sold in packs of 8. Buns are sold in packs of 10. What is the least number of chicken patties & buns

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3 years ago

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How to graph 3 points <br> f (x) = -2x + 5

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4 years ago

21. A man's income is increased in the ratio 47:40. Find the increase percentage. hok= 2:5. x.y =3:4 and 2h+x:(+2y = 1:2. find t

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3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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5 0

2 years ago

X + y = 21 6x +4y=104​

X + y = 21 6x +4y=104