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dimaraw [331]
3 years ago
13

If your front lawn is 17.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1050 new snowflakes every minu

te, how much snow, in kilograms, accumulates on your lawn per hour? Assume an average snowflake has a mass of 2.00 mg.
Mathematics
1 answer:
Alexus [3.1K]3 years ago
3 0

Answer: 42.84 kg

Step-by-step explanation: Lawn is 17 ft x 20 ft.

Its area is S = 17 x 20 = 340 ft²

Each ft² of lawn accumulates 1050 snowflakes/min, 1ft² = 1050 s.f./min.

As 1 hour has 60 min, the lawn accumulates 63000/hour →

1050 x 60 = 63000

1ft² = 63000s.f./hour

This way, 340 ft² of lawn will accumulate 21,420,000 s.f/hour →

340 x 63000 = 21420000

As 1 snowflake has 2mg,  21,420,000 will have 42,840,000 mg.

As 1kg = 1,000,000 mg

42,840,000/1,000,000 = 42.84 kg

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pls I need a answer pls I will brainliest if your answer is correct and if your answer is nonsense i will report you​
VARVARA [1.3K]

Answer:

Using colon

1. 2:18 = 10:60

2. 300:3=400:4

3. 3:5=6:10

4. 39:3=78:6

5. 24:3=32:4

Using fractions

1.2/18 =10/60

2.300/3=400/4

3.3/5=6/10

4. 39/3=78/6

5.24/3=32/4

4 0
2 years ago
Why is he wrong? What is the correct answer?
Tems11 [23]

Answer:

Step-by-step explanation:

He had the incorrect slope for the second line, his line has a positive slope of one while the equation has a slope of negative 1.

x+y=1

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He graphed x+1 instead of -x+1

If he graphed them correctly the lines would intersect when the equations were equal

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3x+4=1

3x=-3

x=-1, making y=2x+4 become

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4 0
3 years ago
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xz_007 [3.2K]

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

the triangles are directly porportional.

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3 0
4 years ago
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GalinKa [24]

Answer:

16

Step-by-step explanation:

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3 years ago
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