Answer:
3r^2 /2
Step-by-step explanation:
r^3 cancels out r in the denominator remaining with r^2 in the numerator.
so 3r^2/2
= 3r^2 /2
Answer:
f(x) = 6x² - 24x + 21
Step-by-step explanation:
The equation of a quadratic function in vertex form is
f(x) = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k ) = (2, - 3 ) , then
f(x) = a(x - 2)² - 3
To find a substitute (1, 3 ) into the equation
3 = 1(1 - 2)² - 3
3 = a(- 1)² - 3
3 = a - 3 ( add 3 to both sides )
6 = a
f(x) = 6(x - 2)² - 3 ← in vertex form
= 6(x² - 4x + 4) - 3
= 6x² - 24x + 24 - 3
f(x) = 6x² - 24x + 21 ← in standard form
Let's solve this question by step by step.
Layout equation.
−104=−8(k+8)
Step 1: Simplify both sides of the equation.
−104=−8(k+8)
−104=(−8)(k)+(−8)(8)(Distribute)
−104=−8k+−64
−104=−8k−64
Step 2: Flip the equation.
−8k−64=−104
Step 3: Add 64 to both sides.
−8k−64+64=−104+64
−8k=−40
Step 4: Divide both sides by -8.
-8k/-8=-40/-8
The answer for this problem is k=5.
As you know, 4.78 is less than 5, so
.. yes, x=4.78 is a solution to x < 5
As you know, 6 = 6, but is not less than 6.
.. no, x=6 is not a solution to x < 6.
It is 3.9 I hope this will help you
