Answer:
The acceleration due to gravity of that planet is, gₐ = 1.25 m/s²
Explanation:
Given that,
Mass of the planet, m = 1/2M
Radius of the planet, r = 2R
Where M and R is the mass and radius of the Earth respectively.
The acceleration due to gravity of Earth, g = 10 m/s²
The acceleration due to gravity of Earth is given by the relation,
g = GM/R²
Similarly, the acceleration due to gravity of that planet is
gₐ = Gm/r²
where G is the Universal gravitational constant
On substituting the values in the above equation
gₐ = G (1/2 M)/4 R²
= GM/8R²
= 1/8 ( 10 m/s²)
= 1.25 m/s²
Hence, the acceleration due to gravity of that planet is, gₐ = 1.25 m/s²
Answer:
8.56 m/s2
Explanation:
Using law of energy conservation while taking into account of the rotational and translation kinetic energy, when the solid cylinder rolls down the incline we have the potential energy converted to kinetic energy:
where m is the mass, 
is the moments of inertia of the solid cylinder 
is the angular speed of the cylinder
So if you plot a liner chart of h vs 
and get a slope of 6.42 then that means 3/(4g) = 6.42 so 
The gravitational acceleration on this planet is 8.56 m/s2
Explanation:
cellulose and pectin are present on the cells of collenchyma...
Answer: You could tell if you made an error in your calculations by repeating the steps.
Speed of light is the fastest/maximum in vacuum which is equal to 3 × 10^8 m/s, therefore speed of light through any material equal to 4 × 10^8 m/s is physically and theoretically impossible and therefore incorrect.
Explanation:
