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Vanyuwa [196]
3 years ago
14

A law enforcement officer in an intergalactic "police car" turns on a red flashing light and sees it generate a flash every 1.2

s. A person on earth measures that the time between flashes is 2.2 s. How fast is the "police car" moving relative to the earth?
Physics
1 answer:
butalik [34]3 years ago
3 0

Answer:

The velocity of the police car relative to earth is v_{rel} = 2.51\times 10^{8} m/s

Given:

time for flash generation of the inter galactic police car, t = 1.2 s

time between flashes as measured from earth, t' = 2.2 s

Solution:

Utilising Einstein's equation for time dilation to calculate the velocity of the police car, the equation is given by:

t' = \frac{t}{\sqrt {1 - \frac{v^{2}}{c^{2}}}}                                (1)

where, c = speed of light in vacuum = c = 3\times 10^{8}

re arranging eqn (1) for velocity, v:

v_{rel} = c\times \sqrt {1 - (\frac{t}{t'})^{2}}                               (2)

Now, from eqn (2)

v_{rel} = 3\times 10^{8}( \sqrt {1 - (\frac{1.2}{2.2})^{2}})

v_{rel} = 3\times 10^{8}\times 0.838

v_{rel} = 2.51\times 10^{8} m/s

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A student tosses a ball horizontally from a balcony to a friend 3.8 meters down below them. How long does the ball take to reach
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Answer:

The time it takes the ball to fall 3.8 meters to friend below is approximately 0.88 seconds

Explanation:

The height from which the student tosses the ball to a friend, h = 3.8 meters above the friend

The direction in which the student tosses the ball = The horizontal direction

Given that the ball is tossed in the horizontal direction, and not the vertical direction, the initial vertical component of the velocity of the ball = 0

The equation of the vertical motion of the ball can therefore, be represented by the free fall equation as follows;

h = 1/2 × g × t²

Where;

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t = The time of motion to cover height, h

Then height is already given as h = 3.8 m

Substituting gives;

3.8 = 1/2 × 9.81 × t²

t² = 3.8/(1/2 × 9.81) ≈ 0.775 s²

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A 117 kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 62.
Ivenika [448]

Answer:

I_syst = 278.41477 kg.m²

Explanation:

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Moment of inertia here is;

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I1 = 117 × 1.61²/2

I1 = 151.63785 kg.m²

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Moment of inertia here is;

I2 = m2•r²

I2 = 62.5 × 1.05²

I2 = 68.90625 kg.m²

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I3 = 28.3 × 1.43²

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Thus,moment of inertia of the system;

I_syst = I1 + I2 + I3

I_syst = 151.63785 + 68.90625 + 57.87067

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8 0
3 years ago
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