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san4es73 [151]
4 years ago
15

Suppose mass and radius of the planet are half and twice that of earth's respectively. If acceleration due to gravity of the ear

th is 10m/S2. Find acceleration due to gravity of that period
Physics
1 answer:
stich3 [128]4 years ago
3 0

Answer:

The acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

Explanation:

Given that,

Mass of the planet, m = 1/2M

Radius of the planet, r = 2R

Where M and R is the mass and radius of the Earth respectively.

The acceleration due to gravity of Earth, g = 10 m/s²

The acceleration due to gravity of Earth is given by the relation,

                                       g = GM/R²

Similarly, the acceleration due to gravity of that planet is

                                        gₐ = Gm/r²

where G is the Universal gravitational constant

On substituting the values in the above equation

                                        gₐ = G (1/2 M)/4 R²

                                             = GM/8R²

                                             = 1/8 ( 10 m/s²)

                                             = 1.25 m/s²

Hence, the acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

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How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 162 mL of coffee at 94.6°C so that the r
Andre45 [30]

Answer:

The volume of water is 139 mL.

Explanation:

Due to the Law of conservation of energy, the heat lost by coffee is equal to the heat gained by the water, that is, the sum of heats is equal to zero.

Q_{coffee} + Q_{water} = 0\\Q_{coffee} = - Q_{water}

The heat (Q) can be calculated using the following expression:

Q=c \times m \times \Delta T

where,

c is the specific heat of each substance

m is the mass of each substance

ΔT is the difference in temperature for each substance

The mass of coffee is:

162mL.\frac{0.997g}{mL} = 162g

Then,

Q_{coffee} = - Q_{water}\\c_{c} \times m_{c} \times \Delta T_{c} = -c_{w} \times m_{w} \times \Delta T_{w}\\m_{c} \times \Delta T_{c} = -m_{w} \times \Delta T_{w}\\m_{w} = \frac{m_{c} \times \Delta T_{c}}{-\Delta T_{w}} \\m_{w}=\frac{162g \times (62.5 \°C - 94.6 \°C ) }{-(62.5 \°C - 25.0 \°C)} \\m_{w} = 139 g

The volume of water is:

139g.\frac{1mL}{0.997g} =139mL

7 0
4 years ago
The magnitude of the resultant force is to be 200 N, directed along the positive ݒaxis. Determine the magnitude of the force Fin
Ilia_Sergeevich [38]

Answer: F = 776.18N θ = 29.41°

Question:

The magnitude of the resultant force is to be 200 N, directed along the positive y-axis. Determine the magnitude of the force F Find the angle θ.

Attached is the image.

Explanation:

To solve this question we need to resolve the forces to the x and y axis.

For the x axis;

Fcosθ = 700cos15....1

For the y axis;

200 = Fsinθ - 700sin15

Fsinθ = 200 + 700sin15 ...2

Dividing equation 2 by 1

Fsinθ/Fcosθ = (200 + 700sin15)/700cos15

Tanθ = (200 + 700sin15)/700cos15

θ = Taninverse(200 + 700sin15)/700cos15)

θ = 29.41°

From equation 1;

F = 700cos15/cosθ

F = 700cos15/cos29.41

F = 776.18N

3 0
4 years ago
What causes reactants to gain potential energy?
Vinvika [58]
The energy of position, stored energy. e.g. exhibited by the position of electrons in electron shells relative to the atom's nucleus.
4 0
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Sound wave frequency difference
motikmotik
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When two objects made of different materials are rubbed together, they will attract each other after the charging process.Immers
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Answer:

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